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Tom [10]
3 years ago
8

Give example of a compound

Chemistry
1 answer:
MrMuchimi3 years ago
3 0

Answer:

The seven crystal systems are a method of classifying crystals according to their atomic lattice or structure. The atomic lattice is a three dimensional network of atoms that are arranged in a symmetrical pattern. The shape of the lattice determines not only which crystal system the stone belongs to, but all of its physical properties and appearance. In some crystal healing practices the axial symmetry of a crystal is believed to directly influence its metaphysical properties. For example crystals in the Cubic System are believed to be grounding, because the cube is a symbol of the element Earth.

Explanation:

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What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL sa
almond37 [142]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 1.25 mL

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of stomach acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.1M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.1\times 25\\\\V_1=\frac{1\times 0.1\times 25}{1\times 2}=1.25mL

Hence, the volume of HCl neutralized is 1.25 mL

3 0
3 years ago
A 0.0200 gram piece of unknown alkaline earth metal, M, is reacted with excess 0.500 M H 2 SO 4 , and the hydrogen gas produced
Rama09 [41]

Answer:

0.981atm

Explanation:

According ot Dalton's law total pressure of a mixture of non-reactive gas is equal to sum of partial pressures of individual gases.

total pressure= 1.01at

Number of gases=2

Gases: water vapor and hydrogen

partial pressure of water vapor= 0.029atm

1.01= partial pressure of water vapor+ partial pressure of hydrogen

1.01= 0.029 + partial pressure of hydrogen

partial pressure of hydrogen = 0.981atm

6 0
3 years ago
Can mercury turn on a light?
PilotLPTM [1.2K]

Answer:

Mercury is useful in lighting because it contributes to the bulbs' efficient operation and life expectancy. Fluorescent and other mercury-added bulbs are generally more energy efficient and last longer than incandescent and other equivalent forms of lighting.

Explanation:

3 0
3 years ago
Single covalent bonds are also referred to as ___________.
liubo4ka [24]

Answer:

Single covalent bond are also referred to as sigma bonds

8 0
3 years ago
Read 2 more answers
If 5.12 g of oxygen O2 gas occupies a volume of 6.21L at a certain temperature and pressure, how many grams of oxygen gas will o
ddd [48]

Answer : The mass of O_2 occupy 30.3 L under the same conditions will be, 24.9 grams.

Explanation :

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}=\frac{5.12g}{32g/mol}=0.16mol

Now we have to calculate the moles of O_2 in 30.3 L by using Avogadro's law.

Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

V\propto n

or,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1 = initial volume of gas = 6.21 L

V_2 = final volume of gas = 30.3 L

n_1 = initial moles of gas = 0.16 mol

n_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{6.21L}{0.16mol}=\frac{30.3L}{n_2}

n_2=0.781mol

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

Molar mass of O_2 = 32 g/mol

\text{ Mass of }O_2=(0.781moles)\times (32g/mole)=24.9g

Therefore, the mass of O_2 occupy 30.3 L under the same conditions will be, 24.9 grams.

6 0
3 years ago
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