The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 1.25 mL
<u>Explanation:</u>
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of stomach acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the volume of HCl neutralized is 1.25 mL
Answer:
0.981atm
Explanation:
According ot Dalton's law total pressure of a mixture of non-reactive gas is equal to sum of partial pressures of individual gases.
total pressure= 1.01at
Number of gases=2
Gases: water vapor and hydrogen
partial pressure of water vapor= 0.029atm
1.01= partial pressure of water vapor+ partial pressure of hydrogen
1.01= 0.029 + partial pressure of hydrogen
partial pressure of hydrogen = 0.981atm
Answer:
Mercury is useful in lighting because it contributes to the bulbs' efficient operation and life expectancy. Fluorescent and other mercury-added bulbs are generally more energy efficient and last longer than incandescent and other equivalent forms of lighting.
Explanation:
Answer:
Single covalent bond are also referred to as sigma bonds
Answer : The mass of 
occupy 30.3 L under the same conditions will be, 24.9 grams.
Explanation :
First we have to calculate the moles of
Now we have to calculate the moles of in 30.3 L by using Avogadro's law.
Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.
or,
where,
= initial volume of gas = 6.21 L
= final volume of gas = 30.3 L
= initial moles of gas = 0.16 mol
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
Now we have to calculate the mass of
Molar mass of = 32 g/mol
Therefore, the mass of occupy 30.3 L under the same conditions will be, 24.9 grams.
