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Rainbow [258]
4 years ago
5

A junction point in the wire of a circuit has inward current of 5.0 A. Which is true? The outward current must be 5.0 A. The out

ward current can be more than 5.0 A. The outward current can be less than 5.0 A.
Physics
1 answer:
Vikki [24]4 years ago
3 0

Answer:

The outward current must be 5.0 A

Explanation:

-A junction is a point where at least three circuit paths meet.

-According to Kirchhoff's Junction Rule & the Law of Charge Conservation:

-The outward current must always equal the inward current because charge is conserved and current measures the rate at which charges are flowing.

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3 years ago
What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.12 m whose potential is 230
slamgirl [31]

Answer:

(a) q=3.07 nC

(b) σ=17 nC/m²

Explanation:

Given data

Radius r=0.12m

Potential V=230 V

To find

(a) Charge q

(b) Charge density σ

Solution

For Part (a)

As we know that potential is:

V_{potential}=k_{constat}\frac{q_{charge}}{r_{radius}} \\\\q_{charge}=\frac{V_{potential*r_{radius}}}{k_{constant}}

Substitute the given values

q_{charge}=\frac{(0.12m)(230V)}{9*10^{9} }\\ q_{charge}=3.07*10^{-9}C\\or\\q_{charge}=3.07nC

For Part (b)

The charge density is given by:

σ=q/(4πr²)

Substitute the given values and value of q to find charge density

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=\frac{3.07*10^{-9}C}{4\pi (0.12m)^2}\\ =1.69*10^{-8}C/m^2\\or\\=17nC/m^2

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