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3 years ago

9

A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, wha

t is their combined velocity immediately after the collision?

1 answer:

g100num [7]3 years ago

5 0

Use conservation of momentum ;

m1u1 + m2u2 = m1v1 + m2v2

1200×15.6 + 0 = 2700v

v = 18720/2700

v = 6.933 or ~ 7 m/s

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What is the angular displacement of the wheel between t = 5 s and t = 15 s?

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The question seems incomplete. The complete text is:

a)What is the angular displacement of the wheel between t = 5 s and t = 15 s

b)What is the angular velocity of the wheel at 15 s

And it refers to the attached figure.

a) 25 rad

The graph shown represent the angular position of the wheel at different times.

Therefore, we can simply calculate the angular displacement between two times by calculating the difference between the angular position at t2 and the angular position at t1.

At $t_1 = 5 s$ , the angular position from the graph is $\theta_1 = 100 rad$

At $t_2 = 15 s$ , the angular position from the graph is $\theta_2 = 125 rad$

Therefore, the angular displacement is

$\Delta \theta= \theta_2 - \theta_1 = 125-100 = 25 rad$

2) -5.0 rad/s

For a angular displacement vs time graph, the angular velocity at any time is simply equal to the slope of the curve at that time.

Here we want to calculate the angular velocity at t = 15 s, so we have to calculate the slope at that time.

By noting that the slope is constant in the last part of the motion, we find that the slope between 10 s and 20 s is:

$\frac{\Delta \theta}{\Delta t}=\frac{100 rad - 150 rad}{20 s - 10 s}=-5.0 rad/s$

This slope is constant between 10 s and 20 s, so the angular velocity of the wheel at t = 15 s

$\omega = -5.0 rad/s$

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Answer:

Series combination:

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Parallel combination:

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Explanation:

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$R=\frac{V}{I}$

R = resistance

I = current

V= potential difference(voltage)

There are two types of resistance combinations.

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Series combination: If the ending point of one resistance is connected to the starting point of other resistance that combination is known as series combination.

If R₁,R₂ and R₃ are connected in series combination.

Then equivalent resistance = R₁+R₂+R₃

Parallel combination: If the ending point and the starting point of the all resistance are the same points that combination is known as parallel combination.

If R₁,R₂ and R₃ are connected in parallel combination.

Then equivalent resistance $\frac{1}{R}= \frac{1}{R_1}+ \frac{1}{R_2}+\frac{1}{R_3}$

Here R₁=7Ω and R₂=3Ω

If R₁ and R₂ connected in series combination

Then equivalent resistance = (7+3) Ω

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If R₁ and R₂ connected in parallel combination

Then equivalent resistance $=\frac{1}{(\frac{1}{7} +\frac{1}{3})} \Omega$

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