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il63 [147K]
3 years ago
10

Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the

red spectrum rom 675 to 700 nm. 1. What is the mean of the wavelength distribution for this radiation? 2. What is the variance of the wavelength distribution for this radiation? 3. If instead, the wavelengths are uniformly distributed at integer nanometers from 75 to 100 nanometers, how do the mean and variance of the wavelength distribution compare to the original distribution? Briefly explain.
Physics
1 answer:
Finger [1]3 years ago
7 0

Answer: See explanation

Explanation:

1. What is the mean of the wavelength distribution for this radiation?

Mean = (a+b)/2

= (675 + 700)/2

= 1375/2

= 687.5

2. What is the variance of the wavelength distribution for this radiation?

Variance= {(b-a+1)^2 - 1}/12

= {(700 - 675 + 1)-1}^2/12

= (26^2)-1/12

= 676-1/12

= 675/12

= 56.25

3. If instead, the wavelengths are uniformly distributed at integer nanometers from 75 to 100 nanometers, how do the mean and variance of the wavelength distribution compare to the original distribution?

New Mean = (a+b)/2

= (75 + 200)/2

= 175/2

= 87.5

New Variance= {(b-a+1)^2 - 1}/12

= {(100 - 75 + 1)-1}^2/12

= (26^2)-1/12

= 676-1/12

= 675/12

= 56.25

From the solutions, while the mean differs, the variance (56.25) is thesame due to the fact that variance depends on interval length and the first and second question has same interval length.

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An object is floating in equilibrium on the surface of a liquid. The object is then removed and placed in another container, fil
Anestetic [448]

Answer:

The fraction of its volume inside liquid  is increased .

Explanation:

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In the second case , when the body is dipped into liquid of lesser density , in order to balance the weight of body , more volume of liquid will be displaced so that weight of displaced liquid becomes equal to object's weight . So the body floats with greater depth inside liquid . The fraction of its volume inside liquid  is increased .

4 0
3 years ago
If it requires 2.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re
valina [46]

Answer:

16 J

Explanation:

It is given that,

Work done, W = 2 J

A spring is stretched by 2.0 cm from its equilibrium length

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Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :

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The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.

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7 0
3 years ago
answer questions1) The south pole of the steel magnet will be brought closer to the iron nail head. Which pole will be at the po
Anvisha [2.4K]
Answer:

North pole

Explanation:

According to the law of magnetism:

<em>Unlike poles attract while like poles repel</em>

Since the south pole of the steel is brought near the nail, and the nail is meant to attract the steel magnet, the nail domain realigns itself to produce a pole opposite to the pole of the steel magnet brought near it.

Since the North pole is the opposite of the south pole, the North pole will be at the pointed end of the nail so that it can attract the steel magnet.

8 0
1 year ago
What happens when the object is placed at F? Explain your answer.
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Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

6 0
3 years ago
Read 2 more answers
A 50g ball is falling down. As the ball passes a certain distance its potential energy changes for 2J. Calculate this distance.
Paul [167]

potential energy = mass × gravity × height

so, change in potential energy = mass × gravity × change in height

2 = 50 × 10 × Δh

2 ÷ 500 = Δh

Δh = 0.004 m

This distance does depend on the initial velocity of the ball.

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