Answer:
Explanation:
general expression for the ionization energy of any one-electron species.
= z² x ground level energy / n²
z is atomic no , n is energy level .
ground level energy of
H = 1.31 x 10³ kJ/mol
He⁺ = 2² x 1.31 x 10³ kJ/mol = 5.24 x 10³ kJ/mol
Li²⁺ = 3² x 1.31 x 10³ kJ/mol = 1.18 x 10⁴ kJ/mol
b ) the ionization energy of B⁴⁺.
= 5² x 1.31 x 10³ kJ/mol = 32.75 x 10³ kJ/mol
c ) minimum energy required to remove the electron from the n = 3 level of He⁺ per mole
= 5.24 x 10³ / 9 kJ/mol
= 5.82 x 10² kJ/mol
= 5.82 x 10² x 10³ / 6.02 x 10²³ J
.9667 X 10⁻¹⁸ J
= .9667 X 10⁻¹⁸ / 1.6 X 10⁻¹⁹ eV
= 6.042 eV
= 1237.5 / 6.042
= 204.82 nm
=
d )
Answer:
Explanation:
The expression for the root mean square speed is:
R is Gas constant having value = 8.314 J / K mol
M is the molar mass of gas
Molar mass of water vapor = 18.0 g/mol = 0.018 kg/mol
Temperature = ?
m/s
Answer:
The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive.
<em>K</em> = 2.4 × 10^(-72)
<em>Step 1</em>. Determine the <em>value of n
</em>
Zn^(2+) + 2e^(-) → Zn
2Cl^(-) → Cl_2 + 2e^(-)
Zn^(2+) + 2Cl^(-) → Zn + Cl_2
∴ <em>n</em> = 2
<em>Step 2</em>. Calculate <em>K</em>
log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62
<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)
Answer:
Percentage of oxygen = 30%
Percentage of carbon = 30%
Percentage of hydrogen = 40%
Explanation:
Formula:
Percentage of element = given amount / total amount × 100
Given compound:
C₆H₈O₆
Number of atoms of carbon = 6
Number of atoms of hydrogen = 8
Number of atoms of oxygen = 6
Total number of atoms = 20
Percentage of carbon = 6/20 × 100
Percentage of carbon = 30%
Percentage of Hydrogen = 8/20 × 100
Percentage of Hydrogen = 40%
Percentage of oxygen = 6/20 × 100
Percentage of oxygen = 30%
