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diamong [38]
3 years ago
6

A center-seeking force related to acceleration is _______ force

Physics
2 answers:
yanalaym [24]3 years ago
6 0
Correct option is (b) centripetal force
34kurt3 years ago
5 0
A because centrifugal is to velocity to how slow or fast something is  and centrifugal has expresssed as ac=v2 / r (1)<span />
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What is the particle arrangement in a liquid
natali 33 [55]

Answer:

the particle arrangement in liquid are close together with no regular arrangement

8 0
3 years ago
What is not a similarity between mars and earth today?
eduard

Answer:

Mars and Earth are two of the planets of the solar system. Some of the ways in which Mars is different from Earth are as follows-

  • The size of the earth is bigger than Mars as Earth has a radius of nearly 6400 km, whereas Mars has a radius of about 3400 km.
  • The atmosphere of earth is primarily comprised of gases such as 78% of Nitrogen (N₂), 21% of Oxygen (O₂), 0.03% of Carbon dioxide (CO₂), and 0.9% of Argon (Ar), whereas the atmosphere of Mars is mainly comprised of 95% of CO₂, 3% of molecular N₂, and 2% of Ar.
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6 0
3 years ago
A small car and a large heavier bus are traveling at the same speed. Which has more momentum?
lions [1.4K]

Answer:

small car since they weigh less than a bus

Explanation:

7 0
2 years ago
In the circuit shown below, 0.25 A of current flows through a 20-Ω resistor. How much voltage is needed to produce this current?
balu736 [363]

Answer:

D 5 V

Explanation:

Without seeing the whole circuit it is impossible to say for certain.

However the simplest circuit would produce a value of

FV = IR = 0.25(20) = 5 v

5 0
3 years ago
24 A uniform electric field of magnitude 1.1×104 N/C is perpendicular to a square sheet with sides 2.0 m long. What is the elect
Tatiana [17]

Answer:

44,000 Nm^2/C

Explanation:

The electric flux through a certain surface is given by (for a uniform field):

\Phi = EA cos \theta

where:

E is the magnitude of the electric field

A is the area of the surface

\theta is the angle between the direction of the field and of the normal to the surface

In this problem, we have:

E=1.1\cdot 10^4 N/C is the electric field

L = 2.0 m is the side of the sheet, so the area is

A=L^2=(2.0)^2=4.0 m^2

\theta=0^{\circ}, since the electric field is perpendicular to the surface

Therefore, the electric flux is

\Phi =(1.1\cdot 10^4)(4.0)(cos 0^{\circ})=44,000 Nm^2/C

4 0
3 years ago
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