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diamong [38]
3 years ago
6

A center-seeking force related to acceleration is _______ force

Physics
2 answers:
yanalaym [24]3 years ago
6 0
Correct option is (b) centripetal force
34kurt3 years ago
5 0
A because centrifugal is to velocity to how slow or fast something is  and centrifugal has expresssed as ac=v2 / r (1)<span />
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A rotating viscometer consists of two concentric cylinders –an inner cylinder of radius Rirotating at angular velocity (rotation
RSB [31]

Answer:

b)  the result we got can be termed approximation because we are neglecting the shear stress acting on the two ends of the cylinder. Here we have considered only the share stress acting on the curved surface area only.

Explanation:

check attachment for solution to A

4 0
3 years ago
What is the average speed of a car that travelled 400 miles in 6 hours?
Reil [10]

Answer:

About 66 miles per hour

Explanation:

Based on the information given we can assume the car traveled the same number of miles every hour meaning all we need to do is divide.

400/6 ≈ 66 miles per hour

8 0
3 years ago
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Which best explains why a wood-burning fireplace does not represent a closed system? A. because a fire requires oxygen from the
sweet [91]
Answer is A of course lol Fire needs oxygen as an essential fuel to burn.
7 0
3 years ago
HURRY PLEASE!!!!!
ycow [4]

Who conducted the study?

Explanation:

One good question to ask the toothpaste making company is who conducted the study?

A company making toothpaste claiming a scientific study revealed that their toothpaste makes the mouth five times cleaner must have introduced a bias in this finding.

  • For a scientific study to be accepted and substantiated, it must have been tested and repeated by other scientists.
  • If no other scientist confirms this, then there is an obvious bias in the claim and it is not scientific.

Learn more:

Objective reporting brainly.com/question/2242789

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7 0
3 years ago
For a brass alloy, the stress at which plastic deformation begins is 345 MPa (50,000 psi), and the modulus of elasticity is 103
Alona [7]

Answer:

a) P = 44850 N

b) \delta l =0.254\ mm

Explanation:

Given:

Cross-section area of the specimen, A = 130 mm² = 0.00013 m²

stress, σ = 345 MPa = 345 × 10⁶ Pa

Modulus of elasticity, E = 103 GPa = 103 × 10⁹ Pa

Initial length, L = 76 mm = 0.076 m

a) The stress is given as:

\sigma=\frac{\textup{Load}}{\textup{Area}}

on substituting the values, we get

345\times10^6=\frac{\textup{Load}}{0.00013}

or

Load, P = 44850 N

Hence<u> the maximum load that can be applied is 44850 N = 44.85 KN</u>

b)The deformation (\delta l) due to an axial load is given as:

\delta l =\frac{PL}{AE}

on substituting the values, we get

\delta l =\frac{44850\times0.076}{0.00013\times103\times 10^9}

or

\delta l =0.254\ mm

3 0
3 years ago
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