Answer:
0.00676 M
Explanation:
A chemist prepares a solution of calcium bromide by weighing out 0.607g of calcium bromide into a 450ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's calcium bromide solution. Be sure your answer has the correct number of significant digits.
Step 1: Given data
Mass of calcium bromide (solute): 0.607 g
Volume of solution: 450 mL
Step 2: Calculate the moles corresponding to 0.607 g of calcium bromide
The molar mass of CaBr₂ is 199.89 g/mol.
0.607 g × 1 mol/199.89 g = 0.00304 mol
Step 3: Convert the volume of solution to liters
We will use the conversion factor 1 L = 1000 mL.
450 mL × 1 L/1000 mL = 0.450 L
Step 4: Calculate the molar concentration of calcium bromide
The molarity of the solution is:
M = moles of solute / liters of solution
M = 0.00304 mol / 0.450 L
M = 0.00676 M
Prokaryotic cells do not contain membrane-closed organelles, (??) and they are not the same size at all. (prokaryotic are way smaller) Just to help narrow down, if I'm right! (: Sorry, I know that's not completely helpful.
Answer:

Explanation:
<u>Given:</u>
Number of atoms =
atoms
Avogadro's Number =
atom / mol
<u>Required:</u>
Moles = ?
<u>Formula:</u>

<u>Solution:</u>

no. of moles = 1.55 moles
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Hope this helped!
<h3>~AH1807</h3>