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3 years ago

Convert 9.32x 10 23ª atoms of au to moles of au

Chemistry

1 answer:

7nadin3 [17]3 years ago

5 0

Answer:

$\huge\boxed{\sf no.\ of\ moles = 1.55\ moles }$

Explanation:

Given:

Number of atoms = $9.32 \times 10^{23}$ atoms

Avogadro's Number = $6.023 \times 10^{23}$ atom / mol

Required:

Moles = ?

Formula:

$\displaystyle No.\ of\ moles = \frac{no. \ of \ atoms }{avogadro's \ no.}$

Solution:

$\displaystyle no. \ of \ moles = \frac{9.32\times 10^{23}}{6.023 \times 10^{23}}$

no. of moles = 1.55 moles

$\rule[225]{225}{2}$

Hope this helped!

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A 17.6-g sample of ammonium carbonate contains ________ mol of ammonium ions.

postnew [5]

These problems are a bit interesting. :)

First let's write the molecular formula for ammonium carbonate.

NH4CO3 (Note! The 4 and 3 are subscripts, and not coefficients)

17.6 gNH4CO3

Now to convert to mol of one of our substances we take the percent composition of that particular part of the molecule and multiply it by our starting mass. This is what it looks like using dimensional analyse.

17.6 gNH4CO3 * (Molar Mass of NH4 / Molar Mass of NH4CO3)

Grab a periodic table (or look one up) and find the molar masses for these molecules! Well. In this case I'll do it for you. (Note: I round the molar masses off to two decimal places)

NH4 = 14.01 + 4*1.01 = 18.05 g/mol
NH4CO3 = 14.01 + 4*1.01 + 12.01 + 3*16.00 = 78.06 g/mol

17.6 gNH4CO3 * (18.05 molNH4 / 78.06 molNH4CO3)
= 4.07 gNH4

Now just take the molar mass we found to convert that amount into moles!

4.07 gNH4 * (1 molNH4 / 18.05 gNH4) = 0.225 molNH4

4 0

3 years ago

In the laboratory you dissolve 13.9 g of potassium phosphatein a volumetric flask and add water to a total volume of 250mL.

tensa zangetsu [6.8K]

Answer:

Molarity of the solution? 0,262 M.

Concentration of the potassium cation? 0,786 M.

Concentration of the phosphate anion? 0,262 M.

Explanation:

Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:

K₃PO₄ → 3 K⁺ + PO₄³⁻ (1)

Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.

There are 250 mL of solution≡0,25 L

The moles of K₃PO₄ are:

13,9 g of K₃PO₄ × $\frac{1mol}{212,27 g}$ = 0,0655 moles of K₃PO₄

The molarity of the solution is:

$\frac{0,0655 moles}{0,25L}$ = 0,262 M

In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:

0,0655 moles×3 = 0,1965 moles

The concentration is:

$\frac{0,1965 moles}{0,25L}$ = 0,786 M

The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M

I hope it helps!

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3 years ago

Scientists often work on projects for a long time and fail to see sources of error in their research. Which process allows an ou

prohojiy [21]

Answer:

The correct approach is Option B (Peer Review).

Explanation:

Rather made reference to someone as a scientific peer-review, it encourages the specialist who has not been essential to the study team to analyze the study objectively and pointed out everyone's mistakes. It serves as major self-regulation for scholars and aims to make the publishing process somewhat credible. Hence, the solution to this issue is Peer Examination.
Funding organizations rarely have the capabilities to recognize out mistakes, whereas definitive analysis is a method of study that helps to make a definitive statement. The gathering of data is simply a process of scientific study.

Other approaches do not apply to the example mentioned. Although the one mentioned is right.

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3 years ago

Read 2 more answers

385 J of heat are needed to heat a piece of aluminum from 22°C to 45°C. If the specific heat of Al is 0.90 J/g°C, what is the ma

VikaD [51]

Answer:

M of Al=33.09g or 0.0331kg

Explanation:

Heat Energy= specific heat*mass*change in temperature

H=M*C*T

make M subject of the formula

M=H/CT

M=685J/0.90J/g°C*(45°C-22°C)

M=685J/0.90J/g°C*23°C

M=685J/20.7J/g

M=33.09g or 0.0331kg

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3 years ago

Identify the name of the compound that goes with this chemical compound

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What is the chemical compound?

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3 years ago