Can u send a picture so I know wat ur talking about
The trend for the radii is Mg²⁺ < Na+ < Ne <F⁻
<h3>What does Ionic size varies with number of protons ?</h3>
With the increase in number of protons in the nucleus the electrons are more attracted towards nucleus and so the ionic radius decreases.
Ionic size increases with the addition of electrons and ionic size decreases with the loss of electrons.
Higher is the atomic number, higher will be the effective nuclear charge, lower will be the size.
F⁻
no. of proton=9
no of electron = 10
Na+
no. of proton=11
no of electron=10
Mg²⁺
no. of proton=12
no of electron=10
Ne
no. of proton=10
no of electron=10
Mg²⁺ < Na+ < Ne <F⁻
Therefore the trend for the radii is Mg²⁺ < Na+ < Ne <F⁻
To know more about effect of protons on Ionic Radius
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Answer:
The C22- ion is stable
Explanation:
The C22- ion is a stable ion having a bond order of three. It has a favourable stabilization energy of 6∆ compared to 4∆ in C2. In the carbide ion carbon firms three bonds rather than two in dicarbon, hence the formation of the carbide ion is preferred. The molecular orbital configuration of the carbide ion is shown in the image attached.
The true statement about the balanced equations for nuclear and chemical changes is; both are balanced according to the total mass before and after the change.
A basic law in science is called the law of conservation of mass. Its general statement is that mass can neither be created nor destroyed.
Both in chemical and nuclear changes, mass is involved and in both cases, the law of conservation of mass strictly applies.
This means that for both chemical and nuclear changes; total mass before reaction must be equal to total mass after reaction.
Hence, both reactions are balanced according to the total mass before and after the change.
Learn more: brainly.com/question/22064431
