To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.
Make sure you calculate the force of gravity on the surface using the radius of the planet.
Answer:
Explanation:
reading of scale = reaction force of surface R
centripetal force = R - mg = m v² / R , m is mass , v is velocity and R is radius of the circular path .
R = mg + m v² / R
given ,
m v² / R = .80 mg
v² = .80 x g x R
= .8 x 9.8 x 9 = 70.56
v = 8.4 m /s
Answer:
a) in the upper position. b) in the lower position. c) in the lower position. d) in the upper position. f) Its kinetic and potential energy will be 0, but the energy is transferred to the element or body that stopped the movement of the pendulum
Explanation:
In the attached image we have the sketch of a pendulum system.
A) The potential energy is maximum when the pendulum is in the upper position (image, fig 1) because the elevation (h) is maximum with respect to the reference point.
B) the potential energy is minimum when the pendulum is in the lower pasition (image, fig 2) because the elevation (h) is cero with respect to the reference point.
Note: When the pendulum is coming down the potential energy is transforming in kinetic energy.
C) The kinetic energy is maximum when the pendulum is in the lower position (image, fig 2), because the potential energy has been transformed in kinetic energy.
D) The kinetic energy is maximum when the pendulum is in the upper position (image, fig 1) because at this moment the pendulum is at rest it means its velocity is 0. We know that the kinetic energy depends on the velocity.
f) The energy is transferred to the element or body that stopped the movement of the pendulum
As per Einstein's relation of relativity

here we know that


now here we know that

now from above equation mass of the muon is given as


now for the momentum of muon we can use



so above is the momentum of muon
Answer:
The minimum force to start the block moving up the wall = 49 N
Explanation:
Friction: This is the force that tend to oppose the motion of two bodies in contact. The S.I unit of frictional force is Newton (N)
The minimum force required to start the block moving up the wall = Frictional Force.
I.e F = Frictional force.
And, F = μR..........................Equation 1
Where μ = coefficient of static friction, R = Normal reaction.
But R = mg ( on a level surface).................. Equation 2
Where m = mass, g = acceleration due to gravity.
Given: m = 10 kg,
Constant: g = 9.8 m/s²
substituting these values into Equation 2
R = 10 × 9.8
R = 98 N.
Also given: μ = 0.50
Substituting these values into equation 1
F = 98 × 0.5
F = 49 N.
Therefore The minimum force to start the block moving up the wall = 49 N