Answer:
intensity of the light (the energy per unit area per unit time)
Explanation:
- The photoflash capacitor is an electrolytic capacitor that is also used in flash cameras, professional illumination and solid-state laser supply. Their general purpose is to briefly power a high-voltage flash tube, which can be used to illuminate photographic material or to alternately pump a laser rod.
- Since the flash tube requires very little time to operate, photoflash capacitors are designed to supply high discharge current pulses without excessive internal heating.
Answer:
i think it might be D or C
Answer:
12 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 7.6 kg
Distance (d) = 6 m
Velocity (v) = 5 m/s
Force (F) = 2 N
Workdone (Wd) =.?
Workdone can be defined as the product of force and distance moved in the direction of the force. Mathematically, it is expressed as:
Workdone = Force × distance
Wd = F × d
With the above formula, we can obtain the workdone as follow:
Distance (d) = 6 m
Force (F) = 2 N
Workdone (Wd) =.?
Wd = F × d
Wd = 2 × 6
Wd = 12 J
Thus, the workdone is 12 J
Explanation:
Here,
object distance(u)=20cm
image distance(v)=80cm-20cm=60cm
focal length(f)=?
we know ,
(1/f)=(1/v)+(1/u)
1/f = 1/60 + 1/20
1/f = (1+3)/60
60 =4f
f=15cm
If the compressor removes 500 j if the 700 the 200 j left would have Ben conducted through the refrigerator/200 j released into the room
