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kramer
3 years ago
6

A force of 12 N changes the momentum of a toy car from 3kgm/s t0 10kgm/s. Calculate the time the force took to produce this chan

ge in momentum.
Physics
1 answer:
yan [13]3 years ago
6 0

Answer:

Time = 0.58 seconds

Explanation:

Given the following data;

Initial momentum = 3 kgm/s

Final momentum = 10 kgm/s

Force = 12 N

To find the time required for the change in momentum;

First of all, we would determine the change in momentum.

Change \; in \; momentum = final \; momentum - initial \; momentum

Change \; in \; momentum = 10 - 3

Change in momentum = 7 kgm/s

Now, we can find the time required;

Note: the impulse of an object is equal to the change in momentum experienced by the object.

Mathematically, impulse (change in momentum) is given by the formula;

Impulse = force * time

Making "time" the subject of formula, we have;

Time = \frac {impulse}{force}

Substituting into the formula, we have;

Time = \frac {7}{12}

Time = 0.58 seconds

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A jumbo jet must reach a speed of 360 km/h on the runway for takeoff. What is the lowest constant acceleration needed for takeof
weeeeeb [17]

The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².

To find the answer, we need to know about the Newton's equation of motion.

<h3>What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?</h3>
  • The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aS
  • V= final velocity, U= initial velocity, S= distance and a= acceleration
<h3>What's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?</h3>
  • Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/s
  • So, 100²-0= 2×a×1800

=> 10000= 3600a

=> a= 10000/3600 = 2.8 m/s²

Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².

Learn more about the Newton's equation of motion here:

brainly.com/question/8898885

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6 0
2 years ago
Is this statement true or false? Electric currents flow easily through materials that are conductors and through materials that
Alex777 [14]
False because currents do not flow easily through insulators. If it only said conductors, then it would be true.
3 0
3 years ago
Read 2 more answers
The first jeans, made by Levi Strauss &amp; Co., were invented in which year?
galina1969 [7]

Answer:

1873

Explanation:

The next time you see someone wearing a pair of Levi's® jeans, remember that these pants are a direct descendant of that first pair made back in 1873. That year, two visionary immigrants — Levi Strauss and Jacob Davis — turned denim, thread and a little metal into what has become the most popular apparel on earth.

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3 years ago
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A motorboat embarks on a trip, heading downstream in a river in which the current flows at a rate of 1.5m/s. After 30.0 minutes,
Natali5045456 [20]

Answer:

t=2413s

Explanation:

From the question we are told that:

Velocity v=1.5m/s

Time t=30min=>30*60=>1800

Distance d=24.3km

Generally the Newton's equation for Speed going down the stream is mathematically given by

 v + u = \frac{d}{t}

 1.5+v=frac{24300}{1800}

 v=12m/s

Therefore

 v + u = \frac{d}{t}

 t=\frac{24300}{12-1.5}

 t=2413s

3 0
3 years ago
A traffic expert wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He a
galben [10]

Answer:

<em>Speed s= 19</em>

<u>Explanation:</u>

Take note of the following parameters:

Speed= s,

Number of cars= N,

Number N of cars that can pass a given spot per minute=

N(s)=88s/16+16(s19)2

The principle of differentiation is  here:

We let N(s) = N

N = 86s / (17 + 17((s/19)^2))

17N = 86s /(1 + s²/19²)

17N = 361* 86s /(361 + s²)

17N = 31046s /(361 + s²)

Next step;

Differentiate with respect to s

17N = 31046s /(361 + s²)

Remember the quotient rule [u/v]’ = (vu’ - uv’) / v²

Therefore,

u = 31046s =====> du/ds = u’ = 31046

v = (361 + s²) ====>dv/ds = v’ = 2s

17N = 31046s /(361 + s²)

17 dN/ds = ( 31046(361 + s²) - 31046s(2s) ) / (361 + s²)²

The maximum when dN/ds = 0

17 dN/ds = ( 31046(361 + s²) - 31046s(2s) ) / (361 + s²)²

17 * 0 = ( 31046(361 + s²) - 31046s(2s) ) / (361 + s²)²

( 31046(361 + s²) - 31046s(2s) ) = 0

31046 [ (361 + s²) - 2s² ] = 0

31046 (361 - s²) = 0

(361 - s²) = 0

(19 - s)(19 + s) = 0

either s = -19 or s = 19, but s > 0

s = 19

4 0
3 years ago
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