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kolezko [41]
3 years ago
7

As the launch force increase the launch velocity will

Physics
1 answer:
klemol [59]3 years ago
3 0

Answer:

take a pic so i can tell u the anwser

Explanation:

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Recall the relationship between the charge on a capacitor and the potential difference across the capacitor. Use this relationsh
charle [14.2K]

Answer:

Answer in explanation.

Explanation:

The relationship between the charge on the capacitor and the potential difference across it is given as follows:

Q = CV

where,

Q = Charge on the Capacitor

C = Capacitance of the Capacitor

V = Potential Difference across the Capacitor

This relationship can be used to find the charge on a capacitor, using the voltmeter, as follows:

<u>The potential difference can be measured through the voltmeter. And the capacitance of the capacitor is a known constant value. Therefore, the charge can be found by taking product of both.</u>

8 0
3 years ago
Which is a concern about mining for uranium? Heated water could be released into the environment. Dust released in the air could
saw5 [17]

Answer: Dust released in the air could be radioactive.

Explanation:

Uranium is a radioactive element. It decays naturally to attain stability. While mining, the dust displaces into the air causing not only harm to environment but for the workers as well. The released in the air could be radioactive which would be inhaled posing threat for lung cancer.

Thus, the correct answer is dust released in the air could be radioactive is a concern about mining Uranium.

3 0
3 years ago
Read 2 more answers
Halogens (Group 17) have<br> valence electrons and will<br> to become stable
Katena32 [7]

Answer:

what is that supposed to even mean

Explanation:

3 0
3 years ago
When the ball is thrown upward and is on the way up what is the direction of it's acceleration?
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5 0
3 years ago
A satellite is to be launched into an orbit of radius,r Show that v = 2gr, where V is the
Snezhnost [94]

Explanation:

We start by using the conservation law of energy:

\Delta{K} + \Delta{U} = 0

or

\dfrac{1}{2}mv^2 - G\dfrac{mM}{r} = 0

Simplifying the above equation, we get

v^2 = 2G\dfrac{M}{r}

We can rewrite this as

v^2 = 2\left(G\dfrac{M}{r^2}\right)r

Note that the expression inside the parenthesis is simply the acceleration due to gravity g so we can write

v^2 = 2gr

where v is the launch velocity.

6 0
3 years ago
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