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LenaWriter [7]
3 years ago
5

An assistant for a football team carries a 26.0 kg cooler of water from the top row of the stadium, which is a distance h = 17.5

m above the field level, down to the bench area on the field. The speed of the cooler is constant throughout the trip. Calculate the work done by the assistant on the cooler of water.
Physics
1 answer:
frozen [14]3 years ago
6 0

The weight of the cooler is (mg). That's (26)(9.8) = 254.8 Newtons.

Its gravitational potential energy while it's up in the top row is (mgh). That's (254.8)(17.5) = 4,459 Joules.

That's how much work it took to get the cooler up to the top row, and that's the energy it gives up when it moves back down to the bench.

In order to bring it down . . .

-- Gravity does 4,459 joules of work on the cooler.

-- The team assistant does NEGATIVE 4,459 joules of work on it.

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PLS HURRY ITS TIMED Sayid recorded the temperatures of four substances in a chart what conclusion best supported by the data?
Vlada [557]

Answer:

WERES THE PICTURE AND WHATS THE CHART!!!

Explanation:

3 0
3 years ago
What is the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosp
sineoko [7]

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

<h3>How to find the weight of a column of air?</h3>
  • As we know that the expression of pressure as,

                 P=\frac{F}{A}

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

  • It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

             P=1atm=1.013*10^5Pascals

  • From this, the value of weight will be,

            F=mg=P*A=1.013*10^5*4.5=4.56*10^5N

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

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4 0
2 years ago
at the instant a traffic light turns green, a car that has been waiting at the intersection starts ahead with a constant acceler
yKpoI14uk [10]

a)  time, t = 11.407 s, b) distance   x = 175.66 m,  v = c)      speed    v = 30.80 m / s

<h3>Explanation of question:</h3>

a) This is kinematics exercise,  write the equation of each vehicle car is;-

 x = x₀ + v₀ t + ½ a t²

Let's fix our the reference system at a point where the car  indicate that the car stops from rest is vo = 0.

 x₀ = v₀ = 0

<h3>we substitute</h3>

x = ½ a t²

truck  

x₂= v₀ t

v₀ = 15.4 m / s

At the point where they are,  positions are equal:-

½ a t² = vo t

t = 2 vo / a

calculate us

t = 2 15.4 / 2.

t = 11.407 s

b) the distance to reach it

x = ½ to t²

x = ½ 20 11.407²

x = 175.66 m

c)  the speed of the car is

 v = vo + a t

  vo = 0

    v = at

      v = 2.0 11.407

       v = 30.80 m / s

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7 0
1 year ago
What is the relative humidity if the dry-bulb temperature is 18°C and the wet-bulb temperature is 11°C?
Diano4ka-milaya [45]

Answer:

The amount of moisture air can hold is dependent on its temperature and pressure. The warmer the air the greater the quantity of water vapour it can contain. The air temperature is measured with a normal thermometer this is the Dry-Bulb reading. The actual amount of moisture known as the mixing ratio is measured in grams of water per kilogram of dry air. When air at a certain temperature is saturated it cannot hold any more moisture. The relative humidity of the air is the ratio of the actual amount of moisture in the air to the fully saturated amount.

We can use evaporation to measure the amount of moisture in the air. A wet cloth is placed over the bulb of a thermometer and then air is blown over the cloth causing the water to evaporate. Since evaporation takes up heat, the thermometer will cool to a lower temperature than a thermometer with a dry bulb at the same time and place. The depression in Wet-Bulb temperature allows the humidity to be calculated. If the air is fully saturated (100% relative humidity) the water cannot evaporate, so both the wet and dry bulb temperatures are the same. If the dry and wet bulb temperatures are set to the same value the calculator will show the saturation mixing ratio the amount of water in saturated air at that temperature.

If partly saturated air is cooled without changing its pressure or amount of water vapour, a point is reached when it becomes saturated. The moisture will be given up as dew or ice crystals. This temperature is the Dew Point. This is why condensation will form on a bottle of cold beer, as the air in the vicinity of the bottle is cooled below its dew point. Meteorological reports usually quote the temperature and dew point as well as the station pressure. Moisture content and relative humidity can be calculated from these figures.

The Psychrometer is the name of a device containing both a wet and dry bulb thermometer. This can be a fixed device for meteorology or a handheld sling psychrometer that is often used in air conditioning applications.

Explanation:

7 0
3 years ago
How far does a car travel as it accelerates from rest to 24 m/s in 6 seconds?
____ [38]

Answer:

\boxed{\sf Distance \ travelled = 72 \ m}

Given:

Initial velocity (u) = 0 m/s (Starts from rest)

Final velocity (v) = 24 m/s

Time taken (t) = 6 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\boxed{ \bold{s =  (\frac{v + u}{2} )t}}

By substituting value of v, u & t in the equation we get:

\sf \implies s = ( \frac{24 + 0}{2} ) \times 6 \\  \\  \sf \implies s =  \frac{24}{2}  \times 6 \\  \\  \sf \implies s = 12 \times 6 \\  \\  \sf \implies s = 72 \: m

\therefore

Distance travelled by car (s) = 72 m

7 0
4 years ago
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