Answer:
a) At a given temperature, C₂H₆ has a higher vapor pressure than C₄H₁₀.
Explanation:
<em>Which statement below is true?
</em>
<em>a) At a given temperature, C₂H₆ has a higher vapor pressure than C₄H₁₀. </em>TRUE. C₂H₆ has a lower molar mass than C₄H₁₀ and a higher vapor pressure at most temperatures.
<em>b) The strongest intermolecular attractive forces present in liquid CCl₄ are dipole-dipole forces.</em> FALSE. CCl₄ is nonpolar, so the strongest intermolecular forces are dispersion forces.
<em>c) HCl has a higher boiling point than LiCl.</em> FALSE. LiCl (ionic compound) has a higher boiling point than HCl (covalent compound).
<em>d) H₂O has a greater polarizability than H₂Se.</em> FALSE. Se has a larger atomic radius than O which is why H₂Se has a greater polarizability than H₂O.
<em>e) In general, the stronger the intermolecular attractive forces, the lower the ∆Hºvap.</em> FALSE. In general, the stronger the intermolecular attractive forces, the higher the ∆Hºvap.
Blue, white, yellow, orange, red
Answer:
9.64g
Explanation:
The balanced equation for the reaction is given below:
2NH3 (g) —> 3H2 (g) + N2 (g)
Next, we need to calculate the mass NH3 that decomposed and the mass of H2 produced from the balanced equation. This is illustrated below:
Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol
Mass of NH3 that decomposed from the balanced equation = 2 x 17 = 34g
Molar Mass of H2 = 2x1 = 2g/mol
Mass of H2 produced from the balanced equation = 3 x 2 = 6g.
Now, we can obtain the mass of H2 formed from 54.6g of NH3 as follow:
From the balanced equation above,
34g of NH3 decomposed to produce 6g of H2.
Therefore, 54.6g of NH3 will decompose to produce = (54.6x6)/34 = 9.64g of H2
Therefore, 9.64g of H2 can be obtained from 54.6g of NH3.
