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2 years ago

5

True or false: The rate law for an elementary step can be deduced from its reaction stoichiometry (i.e., from the balanced equat

ion for the step).

1 answer:

Viktor [21]2 years ago

8 0

Answer:

True

Explanation:

When determining rate law, the coefficients in the balanced equation are used to determine how different concentrations affect the rate.

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A certain heat engine operates between 800 K and 300 K. (a) What is the maximum efficiency of the engine? (b) Calculate the maxi

Sholpan [36]

Answer :

(a) The maximum efficiency of the engine is, 62.5 %

(b) The maximum work done is, 0.625 KJ.

(c) The heat discharge into the cold sink is, 0.375 KJ.

Explanation : Given,

Temperature of hot body $T_h$ = 800 K

Temperature of cold body $T_c$ = 300 K

(a) First we have to calculate the maximum efficiency of the engine.

Formula used for efficiency of the engine.

$\eta =1-\frac{T_c}{T_h}$

Now put all the given values in this formula, we get :

$\eta =1-\frac{300K}{800K}$

$\eta =0.625\times 100=62.5\%$

(b) Now we have to calculate the maximum work done.

Formula used :

$\eta =\frac{Q_h-Q_c}{Q_h}=\frac{w}{Q_h}$

where,

$Q_h$ = heat supplied by hot source = 1 KJ

$Q_c$ = heat supplied by hot source

w = work done = ?

Now put all the given values in this formula, we get :

$\eta =\frac{w}{Q_h}$

$0.625=\frac{w}{1KJ}$

$w=0.625KJ$

(c) Now we have to calculate the heat discharge into the cold sink.

Formula used :

$w=Q_h-Q_c$

$Q_c=Q_h-w$

$Q_c=1-0.625$

$Q_c=0.375KJ$

Therefore, (a) The maximum efficiency of the engine is, 62.5 %

(b) The maximum work done is, 0.625 KJ.

(c) The heat discharge into the cold sink is, 0.375 KJ.

4 0

4 years ago

A certain sample of a gas has a volume of 20 L at 0 oC and 1 atm. A plot of the experimental data of its volume against the Cels

creativ13 [48]

Answer:

The absolute zero temperature T = - 269.91° C

Explanation:

From the given information:

The plot of the volume of the experimental data against the celsius temperature can be expressed mathematically as:

V = mT + c

V = 0.0741 × T+c --- (1)

where;

m, which is the straight line of the slope = 0.0741

replacing the value of V to be = 20 L, T= 0.

Then:

20 = 0.0741 × 0 + c

20 = c

From equation (1), replacing the value of c with 20, we have:

V = 0.0741 × T+20

SO, to determine absolute zero temperature: we have the volume to be zero at absolute zero temperature, Thus:

0 = 0.0741 × T+20

0.0741 T + 20 = 0

0.0741 T = - 20

$\mathbf{T = \dfrac{-20}{0.0741}}$

T = - 269.91° C

6 0

3 years ago

Why are most plants green out of all the colors?

Shkiper50 [21]

Answer: Different forms of chlorophyll

Explanation:

Depending on the significance the of the chlorophyll it’s function is to absorb light, which excites electrons in the chlorophyll.

3 0

3 years ago

Read 2 more answers

A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem

Leto [7]

Answer : The final temperature of the copper is, $87.29^oC$

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat gained = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = $0.0923cal/g^oC$

$\Delta T=\text{Change in temperature}$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25^oC$

Now put all the given values in the above formula, we get the final temperature of copper.

$299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)$

$T_{final}=87.29^oC$

Therefore, the final temperature of the copper is, $87.29^oC$

4 0

4 years ago

Calculate the mass in grams of each sample.<br> 4.88x10^20 H2O2 molecules

AleksAgata [21]

4.88x10^20 H2O2 molecules

5 0

4 years ago