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Trava [24]
4 years ago
5

Calculate the force between two touching grapefruits each with a radius of 0.08 meters and a mass of 0.45 kg

Mathematics
2 answers:
Semmy [17]4 years ago
8 0

Answer:

what he said ok that's the answer

Alchen [17]4 years ago
6 0
<h2>Answer:hope this helps</h2>

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1- Tickets cost £18.50 to a music gig. The band sells 189 tickets and the
Elden [556K]

Answer:

The answer is £ 496

Profit ( P) = Selling price (S) - Cost price ( C)

From the above question

Cost price = £3000

To find the selling price multiply the price of one ticket by the number of tickets sold

That's

Selling price = £18.50 × 189 = £3496

So now

Profit = £3496 - £3000 = £ 496

Hope this helps you

5 0
4 years ago
What is the solution set for this inequality
Zanzabum

Answer:

Letter c po sorry nasa daan po kasi ako kaya di po ako makakapag explain

Step-by-step explanation:

Sorry po talaga pero sigurado po ako sa sagot ko

4 0
3 years ago
I could use a little help with this one. i'm rusty.<br> -3(x+2)-7 = 5x + 7
Pie

Answer:

-3(x+2)-7 = 5x + 7

-3x - 6 - 7 = 5x + 7

-3x - 13 = 5x + 7

-20 = 8x

x = -2.5

7 0
3 years ago
Read 2 more answers
ANYONE??
RideAnS [48]
Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height

b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²

Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²

data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft

(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.

Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³

Answer: ≈202.3 ft³
5 0
3 years ago
Identify the end behavior of the function f(x) = 6x^4 - 12x^3 +8x -10
goldfiish [28.3K]

Answer:

Step-by-step explanation:

This is a quartic  equation with a positive coefficient for x^4 so it is shaped like an M xo ir rises to both the left and the right.

4 0
3 years ago
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