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3 years ago

How many nonbonding electron pairs are there in the lewis structure of the peroxide ion, o22−?

2 answers:

8 0

There is 6 non - bonding pairs.
Let me show you one easy method to do this.
o22-, oxygen valence electron = 6 here we have two so total 12, and -2 that means we add electrons so it’s all equal to 14 right.
whenever need to find lone pair, subtract the number you get with the lowest multiple of 8.
here we total 14 valence electron right so lowest multiple of 8 would be 8.
so 14 - 8 = 6 and that is our answer.
Let me know if you have Problem with chemistry.

frosja888 [35]3 years ago

8 0

Answer:

The correct answer is that there are 6 pairs of non-binding electrons.

Explanation:

Hello!

Let's solve this!

In the Lewis structure of hydrogen peroxide we have a simple covalent bond between each of the hydrogen with each of the oxygen. To this is added a simple covalent bond between the oxygen. So we will have:

O22-: this means that we have 6 electrons for each of the oxygen, they are two oxygen so there are 12 electrons and there is a -2 so in total there are 14 electrons.

This must be deducted from the used electrons that are 2 + 2 (with the hydrogen) +2 (of the two oxygen): in total there are six electrons.

14-6 = 8

In other words, there are 4 pairs of non-binding electrons in hydrogen peroxide.

As is the peroxide ion, we must add two freer pairs, which are those that bind with the hydrogen.

The correct answer is that there are 6 pairs of non-binding electrons.

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The decomposition of nitrogen dioxide is described by the following chemical equation: Suppose a two-step mechanism is proposed

Mandarinka [93]

Answer:

<u>first step </u>

NO2(g) ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

Explanation:

<u>first step </u>

NO2(g) ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

8 0

3 years ago

URGENT CHEMISTRY EXPERT!

vovangra [49]

Answer:

Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)

Explanation:

Part 1. Volume of reactant

(a) Balanced chemical equation.

$\rm 2Na_{3}PO_{4} + 3CuCl_{2} \longrightarrow Cu_{3}(PO_{4})_{2} + 6NaCl$

(b) Moles of CuCl₂

$\text{Moles of CuCl}_{2} =\text{ 16.7 mL CuCl}_{2} \times \dfrac{\text{0.200 mmol CCl}_{2}}{\text{1 mL CuCl}_{2}} = \text{3.340 mmol CuCl}_{2}$

(c) Moles of Na₃PO₄

The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

$\text{Moles of Na$_{3}$PO}_{4} = \text{3.340 mmol CuCl}_{2} \times \dfrac{\text{2 mmol Na$_{3}$PO}_{4}}{\text{3 mmol CuCl}_{2}} =\text{2.227 mmol Na$_{3}$PO}_{4}$

(d) Volume of Na₃PO₄

$V = \text{2.227 mmol Na$_{3}$PO}_{4}\times \dfrac{\text{1 mL Na$_{3}$PO}_{4}}{\text{0.300 mmol Na$_{3}$PO}_{4}} = \text{7.42 mL Na$_{3}$PO}_{4} \\\\\text{The reaction requires $\large \boxed{\textbf{7.42 mL Na$_{3}$PO}_{4}}$}$

Part 2. Net ionic equation

(a) Molecular equation

$\rm 2Na_{3}PO_{4}(\text{aq}) + 3CuCl_{2}(\text{aq}) \longrightarrow Cu_{3}(PO_{4})_{2}(\text{s}) + 6NaCl(\text{aq})$

(b) Ionic equation

You write molecular formulas for the solids, and you write the soluble ionic substances as ions.

According to the solubility rules, metal phosphates are insoluble.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)

(c) Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

The net ionic equation is

3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)

7 0

3 years ago

An atom has radius of 227 pm and crystallizes in a body-centered cubic unit cell. What is the volume of the unit cell

sdas [7]

We will see that the volume of the unit cell is 144,070,699.06 pm^3

<h3>How to get the volume of a body-centered cubic unit cell?</h3>

In a body-centered cubic unit cell, the side length of the cube is given as:

$S = \frac{4}{\sqrt{3} } *R$

Where R is the radius of the atom.

And the volume of a cube is the side length cubed, then we can see that the volume of our cube will be:

$V = S^3 = (\frac{4}{\sqrt{3} }*227pm)^3$

Solving that we get:

$V = (\frac{4}{\sqrt{3} }*227pm)^3 = 144,070,699.06pm^3$

This is the approximated volume of the unit cell.

If you want to learn more about unit cell structures, you can read:

brainly.com/question/13110055

5 0

2 years ago

Crude oil is derived from which of the following materials?

QveST [7]

I believe that crude oil is derived from plants because it is made up of a liquid that is found beneath the earth surface so I guess you could go with plants it is not an animal or rock or salt so.. could be brainliest not 100% sure so if you are not sure go with your gut

3 0

3 years ago

How many moles of CaCO3 are needed to react with 12.5 mol SO2

grandymaker [24]

<h3><u>Answer;</u></h3>

= 12.5 Moles of CaSO3

<h3><u>Explanation</u>;</h3>

The reaction between CaCO3 and SO2 is given by the equation.

CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)

The mole ratio between CaCO3 and SO2 is 1 : 1;

1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2

Therefore;

<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>

7 0

3 years ago