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Pavel [41]
3 years ago
6

If a 185-lb patient is prescribed 145mg. What dosage is the patient receiving in mg/kg of his body weight?

Chemistry
1 answer:
Anestetic [448]3 years ago
7 0

Answer:

1.728 mg/kg

Explanation:

First have to convert the patient's weight to kg

1 lb = 0.454 kg

185 lb in kg = 83.9 kg

Then we have to divide the dose per the weight of the patient

145 mg for 83.9 kg =  145/83.9

= 1.728 mg/kg

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12.2 scientific notation
Nadya [2.5K]

This would be 1.22 x 10^1

You simply move the decimal.

If this helped you, please list me as brainliest!

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3 years ago
Answer the question below based on the periodic table entry for bromine.
Shalnov [3]
<span>The number of neutrons bromine will have are equal to
= protons + neutrons
so,
80-35=45</span>
4 0
3 years ago
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How many moles of sulfuric acid (H2SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LiOH)? 2LiOH + H2SO4
den301095 [7]

The correct answer is 3.4 moles of sulfuric acid (H₂SO₄) are needed to react completely with 6.8 moles of lithium hydroxide.  

2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O

The given chemical equation is balanced.  

By using stoichiometry, one can witness the following:  

2 moles of LiOH requires 1 mole of H₂SO₄

So, 6.8 moles of LiOH requires (1/2) × 6.8 = 3.4 moles of H₂SO₄


6 0
3 years ago
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Which is the best example of immiscible liquids?
Artist 52 [7]

The best example of immiscible liquids is

a polar liquid and a nonpolar liquid that do not dissolve into one another.

Explanation:

Immiscible averages that the fluids don't dissolve in each other – oil and water are an example. It is probable to swing up the juices and get them to mix but they soon separate. Departing immiscible liquids is done solely using a separating funnel.

3 0
3 years ago
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1. A student determines the density of water to be 0.966g/ml at a
lions [1.4K]

<u>Answer:</u>

<em>The percentage error in the measurement is 2.4% </em>

<u>Explanation:</u>

The measurement made by the student is 0.966 g/cm^3.

But the actual value of density is 0.943 g/cm^3

The formula to calculate percentage error is  

percentage error = \frac{(measured \ value-actual \ value)}{(actual  \ value)} \times 100

Hence percentage error in this case is given by

<em>Percentage error = \frac{(0.966-0.943)}{0.943} \times 100 </em>

<em>= \frac{0.023}{0.943} \times 100=2.4% </em>

A physical quantities value will be determines by various quantities. If errors are made in measuring any of these quantities there will be error in the measurement of the final physical quantity as well.

Here density of a substance is a derived quantity determined by measuring mass and volume of  that substance.<em> If errors are made in mass and volume measurements the density value will also be erroneous. </em>

4 0
3 years ago
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