Question

Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin foil that measures 10.0cm by 10.0cm and has a mass of 1.091g?

Answer 1

Answer:

15.0 µm

Step-by-step explanation:

Density = mass/volume

        D = m/V     Multiply each side by V

      DV = m        Divide each side by D

        V = m/D

Data:

m = 1.091 g

D = 7.28 g/cm³

 l = 10.0 cm

w = 10.0 cm

Calculation:

(a) Volume of foil

V = 1.091 g  × (1 cm³/7.28 g)

  = 0.1499 cm³

(b) Thickness of foil

The foil is a rectangular solid.

V  = lwh                            Divide each side by lw

h = V/(lw)

   = 0.1499/(10 × 10)

   = 1.50 × 10⁻³ cm           Convert to millimetres

   = 0.015 mm                  Convert to micrometres

   = 15.0 µm

The foil is 15.0 µm thick.