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myrzilka [38]
3 years ago
8

Parking lot a is 1/4 Mile Long and 3/16 miles wide parking lot B is 3/8 mile long and 1/8 mile wide what is the difference betwe

en the areas of parking lot A and B
Mathematics
2 answers:
djyliett [7]3 years ago
7 0

Answer: There is no difference as the difference equals 0.

Step-by-step explanation:

Parking lot a is 1/4 Mile Long and 3/16 miles wide

Area = length × width

= 1/4 × 3/16

= 3/64

Parking lot B is 3/8 mile long and 1/8 mile wide

Area = length × width

= 3/8 × 1/8

= 3/64

Difference between the areas of parking lot A and B will be:

3/64 - 3/64

= 0

There is no difference.

Alja [10]3 years ago
7 0

Answer:

0

Step-by-step explanation:

We know the parking lot has a rectangular area, therefore, what we must do is calculate the area of each one knowing this.

The area is equal to length times width, therefore:

A

aA = 1/4 * 3/16 = 0.047 mi ^ 2

B

aB = 3/8 * 1/8 = 0.047 mi ^ 2

With the result we can realize that the area they have is exactly the same, therefore the difference is 0.

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11
Alexus [3.1K]

Answer:\frac{-7\sqrt{2} }{4}

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get \sqrt{16}-x\sqrt{8} =11. We know that the square root of 16 is ±4, so now our equation is ±4 - x\sqrt{8}=11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - x\sqrt{8}=11. We can use inverse operations to make the a little easier to solve: -7= x\sqrt{8}. We divide both sides by \sqrt{8} to get \frac{-7}{\sqrt{8} } =x, which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by \frac{\sqrt{8} }{\sqrt{8} } (which is equal to one so we can use it) which is equal to \frac{-7\sqrt{8} }{8}. Let's finish this by simplifying it. \sqrt{8} =2\sqrt{2} (2x2^{2}). We can simplify it further by simplifying the 2, making it \frac{-7\sqrt{2} }{4}.

Hope this wasn't too confusing! I'll answer any questions.

8 0
2 years ago
Read 2 more answers
Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.
Romashka [77]

Answer:

<u>(3,7)</u> (7,3) (−1,14) <u>(0,1)</u> <u>(12,25)</u>

<u>(5,11)</u> (0,12) (1,8) (12,0) <u>(−1,−1)</u>

Step-by-step explanation:

We have the following function:

y = 2x+1.

We are going to check if each ordered pair is a solution.

(3,7)

If when x = 3, y = 7, it is a solution.

y = 2x + 1 = 2(3) + 1 = 7

This ordered pair is a solution.

(7,3)

If when x = 7, y = 3, it is a solution.

y = 2x + 1 = 2(7) + 1 = 15

This ordered pair is not a solution.

(-1,14)

If when x = -1, y = 14, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is not a solution.

(0,1)

If when x = 0, y = 1, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is a solution.

(12,25)

If when x = 12, y = 25, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is a solution.

(5,11)

If when x = 5, y = 11, it is a solution.

y = 2x + 1 = 2(5) + 1 = 11

This ordered pair is a solution.

(0,12)

If when x = 0, y = 12, it is a solution.

y = 2x + 1 = 2(0) + 1 = 1

This ordered pair is not a solution.

(1,8)

If when x = 1, y = 8, it is a solution.

y = 2x + 1 = 2(1) + 1 = 3

This ordered pair is not a solution.

(12,0)

If when x = 12, y = 0, it is a solution.

y = 2x + 1 = 2(12) + 1 = 25

This ordered pair is not a solution.

(-1,-1)

If when x = -1, y = -1, it is a solution.

y = 2x + 1 = 2(-1) + 1 = -1

This ordered pair is a solution.

3 0
2 years ago
Anybody know what the answer is
koban [17]
5. million 6. Ten thousand
6 0
3 years ago
Look at photo asap please <br><br><br><br><br><br><br>​
aivan3 [116]

Answer:

option D is correct.

hope it helps

3 0
3 years ago
The permitir of the garden is (6x+2) units. Find the length of the missing side .
Snezhnost [94]

Answer: ? = x + 1


Step-by-step explanation:

The perimeter of the garden is x + 3x + 1 + x + ?

The perimeter of the garden is also (6x + 2)

Therfore:

x + 3x + 1 + x + ? = 6x + 2

<em>Collect like terms: </em>

5x + 1 + ? = 6x + 2

<em>Subtract 5x from both sides:</em>

1 + ? = x + 2

<em>Subtract 1 from both sides:</em>

? = x + 1

You cannot find ? as a number, only in terms of x.

5 0
3 years ago
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