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Damm [24]
3 years ago
11

Current flowing in a circuit depends on two variables. Identify these variables and their relationship to current.

Physics
1 answer:
joja [24]3 years ago
7 0

Question is Incomplete, Complete question is given below.

Current flowing in a circuit depends on two variables. Identify these variables and their relationship to current.

A) Current is proportionate to the conductance of the circuit and precisely proportional to the voltage applied across the circuit.

B) Current is conversely proportional to the electrical tension of the circuit and corresponds to the resistance across the circuit.

C) Current is inversely proportional to the resistance of the circuit and directly proportional to the voltage applied across the circuit.

D) Current is commensurate to the resistance of the circuit and directly proportional to the electric pressure applied across the circuit.

Answer:

C) Current is inversely proportional to the resistance of the circuit and directly proportional to the voltage applied across the circuit.

Explanation:

Now Ohms Law states that, "So long as a physical state of a conductor remains the potential difference applied to the conductor is directly proportional to current flowing through it."

I ∝ V

V=IR also I=V/R

where R is the Resistance

Hence, From above equation we can say that Current increases when there is increase in Voltage but Current decreases as the resistance decreases.

Hence,Current is inversely proportional to the resistance of the circuit and directly proportional to the voltage applied across the circuit.

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Answer:

50 N

Explanation:

Let the force in the horizontal rope be F₁ and the force in the diagonal rope be F₂:

The total force in the horizontal and vertical directions must be zero, since the object is at rest and is not accelerating.

The horizontal component of the forces:

F₁ + F₂ = -40N + F₂ = 0

F₂ = 40N

The vertical component of the forces:

F₁ + F₂ - mg = 0 + F₂ - mg = 0

F₂ = mg

If I assume the gravitational constant g = 10 m/s²:

F₂ = (3 kg) * (10 m/s²) = 30N

Adding the horizontal and vertical components of the force F₂:

F₂ = √((40N)² + (30N)²) = 50N

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An 85-kg rock climber, when reaching the summit, built up 250,000 J of gravitational potential energy. How high did the climber
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What current flows through a 2.56-cm-diameter rod of pure silicon that is 20.0 cm long, when 1.00 ✕ 103 V is applied to it? (Suc
vfiekz [6]

Answer:

Current, I = 0.0011 A

Explanation:

It is given that,

Diameter of rod, d = 2.56 cm

Radius of rod, r = 1.28 cm = 0.0128 m

The resistivity of the pure silicon, \rho=2300\ \Omega-m

Length of rod, l = 20 cm = 0.2 m

Voltage, V=1\times 10^3\ V

The resistivity of the rod is given by :

R=\rho\dfrac{L}{A}

R=2300\ \Omega-m\dfrac{0.2\ m}{\pi (0.0128\ m)^2}

R = 893692.30 ohms

Current flowing in the rod is calculated using Ohm's law as :

V = I R

I=\dfrac{V}{R}

I=\dfrac{10^3\ V}{893692.30\ \Omega}

I = 0.0011 A

So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.

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What is the least amount of time required for a given point on this wave to move from y = 0 to y = 12cm?
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Time t = ?

<span>When wave is moving from y = 0  to y =12 cm</span>

By using the formula,

y = 15cos [(π/12) t)] = 0,

cos [(π/12) t)] = 0 = cos (π/2), so, 

(π/12)t = π/2,

t = (π/2) (12/π) 

t = 12/2

<span>t = 6 sec</span>

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