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alexira [117]
2 years ago
12

Im so confused can someone help. I’ll give you BRAINLIETS

Physics
1 answer:
Hatshy [7]2 years ago
3 0

I found the answer sheet online for you

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The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -41 oC and 900 Pa, respect
Fittoniya [83]

Answer:

Part a)

\rho = 0.0205 kg/m^3

Part b)

\rho = 1.22 kg/m^3

So density of atmosphere at Martian Surface is very less than the density at Earth.

Explanation:

Part a)

As per ideal gas equation we know that

PM = \rho RT

here we know that Martian atmosphere is equivalent to that of carbon

so we will have

P = 900 Pa

T = 273 - 41 = 232 K

now we will have

(900)(0.044) = \rho (8.31)(232)

\rho = 0.0205 kg/m^3

Part b)

Now for the earth surface the density of air is given for

P = 101.6 kPa

T = 18 ^oC

so we will have

PM = \rho RT

(101.6\times 10^3)(0.029) = \rho(8.31)(273 + 18)

\rho = 1.22 kg/m^3

So density of atmosphere at Martian Surface is very less than the density at Earth.

8 0
2 years ago
Define and explain the Police Power
Allushta [10]

Answer:

Police powers are the fundamental ability of a government to enact laws to coerce its citizenry for the public good, although the term eludes an exact definition. The term does not directly relate to the common connotation of police as officers charged with maintaining public order, but rather to broad governmental regulatory power. Berman v. Parker, a 1954 U.S. Supreme Court case, stated that “public safety, public health, morality, peace and quiet, law and order. . . are some of the more conspicuous examples of the traditional application of the police power”; while recognizing that “an attempt to define police powers reach or trace its outer limits is fruitless.”

6 0
2 years ago
Take a close look at the energy transfers and transformations shown in the above diagram. Which type of energy is transformed in
labwork [276]

Kinetic Energy

How to calculate

Kinetic energy is given by K.E.

\\ \sf\longmapsto K.E=\dfrac{1}{2}mv^2

Where

  • m is denoted to mass
  • v is denoted to velocity
4 0
3 years ago
A projectile is launched from ground level at angle u and speed v0 into a headwind that causes a constant horizontal acceleratio
ale4655 [162]

Answer:

Explanation:

Given

Launch angle =u

Initial Speed is v_0

Horizontal acceleration is a_x=a

At maximum height velocity is zero therefore

v_f=v_i-gt

0=v_0\sin u-gt

t=\frac{v_0\sin u}{g}

Total time of flight T=2t=\frac{2v_0\sin u}{g}

During this time horizontal range is

R=v_o\cos u\cdot 2t-\frac{a(2t)^2}{2}

R=\frac{2v_0^2\sin u\cos u}{g}-\frac{2av_0^2\sin ^u}{g^2}

For maximum range \frac{\mathrm{d} R}{\mathrm{d} u}=0

\frac{\mathrm{d} R}{\mathrm{d} u}=\frac{2v_0^2\cos 2u}{g}-\frac{4av_0^2\sin u\cos u}{g^2}

\frac{\mathrm{d} R}{\mathrm{d} u}=\frac{2v_0^2}{g}\left [ \cos 2u-\frac{a}{g}\sin 2u\right ]=0

\tan 2u=\frac{g}{a}

u=\frac{1}{2}tan ^{-1}\frac{g}{a}

(b)If a =10% g

a=0.1g

thus u=\frac{1}{2}tan^{-1}\frac{g}{0.1g}

u=42.14^{\circ}

7 0
3 years ago
1) what is a calorie?<br>​
Bogdan [553]
I read it’s a unit of energy
3 0
3 years ago
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