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Ivanshal [37]
3 years ago
9

You are leading a software development team which uses serverless computing with AWS Lambda to build and run applications withou

t having to set up or manage servers. You have a Lambda function that connects to a MongoDB Atlas, which is a popular Database as a Service (DBaaS) platform and also uses a third party API to fetch certain data for your application. You instructed one of your junior developers to create the environment variables for the MongoDB database hostname, username, and password as well as the API credentials that will be used by the Lambda function for DEV, SIT, UAT and PROD environments.
Considering that the Lambda function is storing sensitive database and API credentials, how can you secure these information to prevent other developers in your team, or anyone, from seeing these credentials in plain text?
Physics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

You can create a new K.M.S key and use it to allow cryptographic assistants using AWS key management to store and encrypt sensitive information.

Explanation:

K.M.S is a computational model that covers more than one server on a local network, which has the power to automatically activate a set of computers that are in the same location and connected to the same network. In summary, a K.M.S key can act as a windows activation server. When a computer is activated by a K.M.S activation key, it will need to be reconnected to a K.M.S host twice a year to renew its activation. This can be very useful for the security of both files and the machine itself.

Regarding the question above, a K.M.S key is the ideal system to be used if you want to protect some information and want to prevent other developers on your team or anyone from seeing your credentials in plain text. To do this, you must create a new K.M.S key and use it to allow cryptographic assistants who use or manage AWS keys to store and encrypt as confidential information.

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A 190 g air-track glider is attached to a spring. The glider is pushed in 9.20 cm and released. A student with a stopwatch finds
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Answer:

k = 12.136\,\frac{N}{m}

Explanation:

The angular frequency of the system is:

\omega = \sqrt{\frac{k}{m} }

The frequency is:

f = \frac{14\,osc}{11\,s}

f = 1.272\,hz

The angular frequency is:

\omega = 2\pi\cdot (1.272\,hz)

\omega = 7.992\,\frac{rad}{s}

The spring constant is:

k = \left(7.992\,\frac{rad}{s} \right)^{2}\cdot (0.190\,kg)

k = 12.136\,\frac{N}{m}

6 0
3 years ago
an elephant with a gravitational force of 4800 N is falling from a high dive. Air resistance is pushing up on the elephant with
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4650N due Earth
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3 years ago
If an object has a mass of 26 g on earth would its mass be less than 26 g on the moon
aleksley [76]

Answer:

No

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8 0
3 years ago
A steel ball with mass m=5.21 g is moving horizontally with speed ????=412 m/s when it strikes a block of hardened steel with ma
docker41 [41]

Answer:

a) The speed of the block immediately after the collision is v_{2f}=(0.289\±0.002)m/s.

b) The impulse exerted on the block is p_{2}=(4.2772\±0.0296)kg*m/s.

Explanation:

Hi

a) As this is a perfectly elastic collision, we can use the formula  v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}+ (\frac{m_{2}-m_{1}}{m_{1}+m_{2}} )v_{2i}, due v_{2i}=0m/s, we obtain v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}. Then with the data that we know m_{1}=5.21g=0.00521kg, m_{2}=14.8kg and v_{1i}=412m/s, therefore v_{2f}=(\frac{2(0.00521kg) }{0.00521kg+14.8kg} ) 412m/s=0.289m/s or v_{2f}=(0.289\±0.002)m/s adding uncertainty.

b) Now that we know the speed we can use p_{2}=m_{2}*v_{f2} =14.8kg*(0.289\±0.002)m/s=(4.2772\±0.0296)kg*m/s.

8 0
4 years ago
Two lamps, each having reisistance of 3 Ohms, connect in a series. What current will flow if a voltage source of 5 V is connecte
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Total resistance will be R1 + R2.
And the formula will be I equals V over R.
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I= 0,83 amps
6 0
3 years ago
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