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3 years ago

How do you do these questions ? i need help:(

Mathematics

1 answer:

IrinaVladis [17]3 years ago

8 0

Answer:

(x,y) all you have to do is fill in the x and y and find the equation it matches to

Step-by-step explanation:

hope this helps plz give brainliest

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The measure of angle A to the nearest tenth of a degree is: A 18.5 B 19.5 C 20.5

Andrew [12]

Answer:

Step-by-step explanation:

This is a right triangle as shown by the right angle.

The side opposite the right angle is the hypotenuse, which is 9.
The side opposite angle A is 3.

So we have the opposite of A and the hypotenuse.

The trigonometric ratio that relates opposite side to hypotenuse is SINE.

$sin\theta=\frac{opposite}{hypotenuse}$

Since, we need angle A, $\theta$ is A, opposite side is 3, and hypotenuse is 9, we substitute:

$sinA=\frac{3}{9}\\sinA=\frac{1}{3}$

To solve for the angle, we use our calculator and find the inverse sin of $\frac{1}{3}$ :

$A=sin^{-1}(\frac{1}{3})\\A=19.47$

Rounding to nearest tenth of a degree:

$A=19.5$

B is the right choice.

6 0

3 years ago

A dairy cow can produce up to 2000 gallons of milk every 365 days. At this rate, a cow can produce x gallons of milk in 500 days

Mariulka [41]

First I cant understand the choices, because on how you type so I will jus provide the answer for you. First the amount of milk produce is proportional to the number of days so

2000 = k(365)

K = 2000 / 365

So to solve for x

X = ( 2000/365) 500

X = 2740

5 0

3 years ago

What is the measure of Arc ABC

svp [43]

Arc ADC measures 295°

4 0

3 years ago

Read 2 more answers

Pls help asap thx :)

Allushta [10]

Answer: a

Step-by-step explanation:

It can show she earn how much each week and how much she earn at the end of the week.

8 0

3 years ago

Simplify completely sqrt of 20Y^8

brilliants [131]

Answer:

Final answer is $2y^4 \sqrt{5}$ .

Step-by-step explanation:

Given expression is $\sqrt{20y^8}$ .

Now we need to smplify the given expression $\sqrt{20y^8}$ .

So begin with factoring 20 into two parts so that one part is perfect square number.

$\sqrt{20y^8}$

$=\sqrt{4 \times 5y^8}$

$=\sqrt{4 y^8} \times \sqrt{5}$

$=2y^4 \times \sqrt{5}$

Hence final answer is $2y^4 \sqrt{5}$ .

3 0

3 years ago