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mash [69]
3 years ago
7

In the lab jill mixed 3 gases together. The resulting pressure was 930 mmHg carbon dioxide had a partial pressure of .70 atm and

oxygen had a partial pressure of 680 mmHg. What is the partial pressure of nitrogen in kPa
Chemistry
1 answer:
SOVA2 [1]3 years ago
3 0

Answer:

26.2kPa is the partial pressure of nitrogen

Explanation:

<em>Assuming the partial pressure of Carbon dioxide is 0.070atm</em>

<em />

The total pressure of a mixture of 3 gases (CO2, O2 and N2) is:

Total pressure = Partial pressure CO2 + Partial pressure O2 + Partial pressure N2

0.070atm CO2 are:

0.070atm * (760mmHg / 1atm) 53.2mmHg

Replacing:

930mmHg = 53.2mmHg + 680mmHg + Partial pressure N2

Partial Pressure N2 = 196.8mmHg

In kPa -101.325kPa = 760mmHg-

196.8mmHg * (101.325kPa / 760mmHg) =

<h3>26.2kPa is the partial pressure of nitrogen</h3>
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How many grams of hydrogen is produced from 12.5 G of MG reacting with hydrochloric acid in this balanced equation?
k0ka [10]

Answer:

1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.

Explanation:

The balanced reaction is:

Mg+ 2 HCl → MgCl₂ + H₂

By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

  • Mg: 1 mole
  • HCl: 2 moles
  • MgCl₂: 1 mole
  • H₂: 1 mole

Being the molar mass of each compound:

  • Mg: 24.31 g/mole
  • HCl: 36.45 g/mole
  • MgCl₂: 95.21 g/mole
  • H₂: 2 g/mole

By reaction stoichiometry, the following mass amounts of each compound participate in the reaction:

  • Mg: 1 mole* 24.31 g/mole= 24.31 g
  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
  • H₂: 1 mole* 2 g/mole= 2 g

Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg produces 2 grams of H₂, 12.5 grams of Mg produces how much mass of H₂?

mass of H_{2} =\frac{12.5 grams of Mg* 2 grams of H_{2}}{24.31 grams of Mg}

mass of H₂= 1.03 grams

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