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Blababa [14]
2 years ago
7

The more quickly you change your _____, the more ____ you will have to exert

Chemistry
1 answer:
tatyana61 [14]2 years ago
5 0

Answer:

name, force

Explanation:

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A compound is determined to have the empirical formula C2OH4. If the molar mass of the compound is 132 g/mol, determine the mole
8_murik_8 [283]

Answer: The molecular formula will be C_6O_3H_{12}

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

Empirical weight of C_2OH_{4} is 12\times 2+16\times 1+1\times 4=44g

Molecular mass of compound is = 132 g

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{132}{44}=3

The molecular formula will be=3\times C_2OH_4=C_6O_3H_{12}

5 0
3 years ago
What kind of simple machine is a shovel
Minchanka [31]
I think a shovel is a wedge simple machine.
8 0
3 years ago
Read 2 more answers
4. Balance the following chemical equation. Say what the coefficients "a"
lisabon 2012 [21]

Answer:

a = 4

b = 3

Explanation:

<u>SOLUTION :-</u>

Balance it by using 'hit & trial' method , and you'll get the answer :-

2Fe₂O + 3C → <u>4</u>Fe + <u>3</u>CO₂

⇒ a = 4 ; b = 3

<u></u>

<u>VERIFICATION :-</u>

<em>In reactant side of equation :-</em>

  • Number of atoms in Fe = 2×2 = 4
  • Number of atoms in O = 2×3 = 6
  • Number of atoms in C = 3×1 = 3

<em>In product side of equation :-</em>

  • Number of atoms in Fe = 4×1 = 4
  • Number of atoms in C = 3×1 = 3
  • Number of atoms in O = 3×2 = 6

Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.

6 0
3 years ago
One of the method used for the manufacturing of steel is the
Norma-Jean [14]
The answer is B. Centrifugation
7 0
2 years ago
How many moles of silver nitrate (AgNO3) are needed to produce 6.75 moles of copper (ll) nitrate (Cu(NO3)2) upon reacting with e
Alina [70]

Answer:

13.5 moles of AgNO₃

Explanation:

To determine the reaction:

Reactants: AgNO₃ and Cu

Products: Cu(NO₃)₂ and Ag

2 moles of AgNO₃ react to 1 mol of Cu, in order to produce 1 mol of Cu(NO₃)₂ and 2 moles of solid silver.

2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag

Our production was 6.75 moles of Cu(NO₃)₂

Let's make the rule of three:

1 mol of Cu(NO₃)₂ is produced by 2 moles of AgNO₃

Then, our 6.75 moles were definetely produced by (6.75 . 2) /1 = 13.5 moles.

If the copper was in excess, then the silver nitrate is the limiting reactant:

2 mol of AgNO₃ can produce 1 mol of Cu(NO₃)₂

Then, 13.75 moles of silver nitrate must produce (13.5 . 1) /2 = 6.75 moles of Cu(NO₃)₂

6 0
3 years ago
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