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3 years ago

What is the ideal gas law?

2 answers:

5 0

The law that the product of the pressure and the volume of one grammolecule of an ideal gas is equal to the product of the absolutetemperature of the gas and the universal gas <span>constant.</span>

ladessa [460]3 years ago

3 0

The ideal gas law is as follows:
PV=nRT
P=pressure
V=volume in Liters
n=number of moles
R= constant, .0821 atm x moles x K
T=temperature in Kelvin

It is a model for real gases that have low densities.

Hope this helps :)

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gizmo_the_mogwai [7]

Possibly decomposition but not sure

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3 years ago

Read 2 more answers

A point has no demension.

Natalka [10]

Answer:

A point is a 0-D object, infinitely small.

Explanation:

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3 years ago

How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac

Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

• using the molar mass of Ca(OH)2 (74g/mol).

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

• using the molar mass of HNO3 (63.02g/mol).

$4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3$

So, 7.32g of HNO3 are required.

4 0

2 years ago

Give evidence to support or dispute: “In nature, the chance of finding one isotope of an element is the same for all elements.”

alekssr [168]

Answer:

False, isotopes have different occurrence percentages, so the changes are different.

Explanation:

Hello,

In this case, since it is false that the isotopes of all the elements can be found with the same chance (occurrence) we can consider the following facts:

1. Carbon atom has two major occurring isotopes: C-12 (98.93%) and C-13 (1.07%).

2. Bromine atom has two major occurring isotopes: Br-79 (50.69%) and Br-81 (49.31%).

3. Calcium has four major occurring isotopes: Ca-40 (96.941%), Ca-42 (0.647%), Ca-43 (0.135%) and Ca-44 (2.086%).

Which show us that the chances of finding any isotope differ among elements.

Regards.

5 0

3 years ago

Please please help !!!

lubasha [3.4K]

Answer:

They don't go below 60

Explanation:

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3 years ago