Answer:
<h2>
Kevlar has unique properties such as:</h2><h2><em>
High tensile strength</em>
, <em>
high toughness</em>
, and <em>
chemical stability </em>
at high temperatures<em>
</em>
in polyamides (polymer with repeating unit links by amide bonds.) </h2><h3>
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Δ What is Kelvar? Δ
~ Kevlar is a heat-resistant and strong synthetic fiber
~ Kevlar is widely used as a friction material in the automotive industry, and a combustion protection material in the aerospace industry. <em>~Looked that up!</em>
<h3>
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<em>Hope I helped!!!</em>
<em>GL :)</em>
First, recognize that this is an elimination reaction in which hydroxide must leave and a double bond must form in its place. It is likely an E2 reaction. Here is an efficient mechanism:
1) Pre-reaction: Protonate the -OH to make it a good leaving group, water. H2SO4 or any strong H+ donor works. The water is positively charged but still connected to the compound.
2) E2: Use a sterically hindered base, such as tert-butoxide (tButO-) to abstract the hydrogen from the secondary carbon. [You want a sterically hindered base because a strong, non-sterically hindered base could also abstract a hydrogen from one of the two methyl groups on the tertiary carbon, and that leads to unwanted products, which is not efficient]. As the proton of hydrogen is abstracted, water leaves at the same time, creating an intermediate tertiary carbocation, and the 2 electrons in the C-H bond immediately are used to make a double bond towards the partial positive charge.
In the products we see the major product and water, as expected. Even though you have an intermediate, remember that an E2 mechanism technically happens in one step after -OH protonation.
Answer:
Car 3 with a net force of 12N
Explanation:
The formula is F=MA
Hope this helps friend
<span>You need to have NAD+ as a source of oxidation for the pyruvate, as well as a supply of coenzyme A. CO2 is released by the pyruvate as a carboxyl group is removed</span>
Answer:
3 moles
Explanation:
SrCO3
Mass = 442.8g
Molar mass = (87.6 + 12 * [16*3]) = 147.6g/mol
Number of moles = mass / molar mass
Number of moles = 442.8 / 147.6
Number of moles = 3