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zhuklara [117]
3 years ago
11

What is the ideal gas law?

Chemistry
2 answers:
REY [17]3 years ago
5 0
The law that the product of the pressure and the volume of one grammolecule of an ideal gas is equal to the product of the absolutetemperature of the gas and the universal gas <span>constant.</span>
ladessa [460]3 years ago
3 0
The ideal gas law is as follows:
PV=nRT
P=pressure
V=volume in Liters
n=number of moles
R= constant, .0821 atm x moles x K
T=temperature in Kelvin

It is a model for real gases that have low densities.

Hope this helps :)
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An herbicide contains only C, H, Cl, and N. The complete combustion of a 200.0 mg sample of the herbicide in excess oxygen produ
MAVERICK [17]

Answer:

%C = 56,1%

%H = 5,5%

%Cl = 27,6%

%N = 10,8%

Explanation:

The moles of CO₂ are the same than moles of C in the herbicide.

Moles of H₂O are ¹/₂ of moles of H in the herbicide.

Moles of CO₂ are obtained using:

n = PV/RT

Where, in STP: P is 1 atm; V is 0,2092L; R is 0,082atmL/molK; T is 273 K

moles of CO₂ are: 9,345x10⁻³ mol≡ mol of C×12,01g/mol = <em>0,1122 g of C ≡ 112,2mg of C</em>

In the same way, moles of H₂O are 5,450x10⁻³mol×2 =0,1090 mol of H×1,01g/mol = <em>0,0110 g of H ≡ 11,0mg of H</em>

As you have 55,14 mg of Cl, the mg of N are:

200,0mg - 112,2 mg of C - 11,0 mg of H - 55,14 mg of Cl = 21,66 mg of N

Thus, precent composition of the herbicide is:

%C = \frac{112,2 mgC}{200,0mg}×100 = 56,1%C

%H = \frac{11,0 mgH}{200,0mg}×100 = 5,5%H

%Cl = \frac{55,14 mgCl}{200,0mg}×100 = 27,6%Cl

%N = \frac{21,66 mgN}{200,0mg}×100 = 10,8%N

I hope it helps!

3 0
3 years ago
Is H20 a balanced equation?
Nat2105 [25]

Answer:

no it's not

Explanation:

because H2+O2=H2O

so the balanced form is

H2 +O2=2H2O

8 0
3 years ago
Help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
tangare [24]

Answer:

A

Explanation:

4 0
3 years ago
Read 2 more answers
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