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Dmitriy789 [7]
3 years ago
14

Spindle fibers break down during what phase?

Chemistry
2 answers:
matrenka [14]3 years ago
8 0
The answer is Prophase
Rasek [7]3 years ago
7 0
Answer: Prophase.
In prophase, chromosomes condense and become visible. Spindle fibers emerge from the centrosomes.
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A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil
Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V_1 ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n_2 ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V_1 ) = 1.50 L,

Initial moles ( n_1 ) = 3.00 mol,

Final Volume ( n_2 ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V_2 ).

P_1V_1 / n_1T_1 = P_2V_2 / n_2T_2 - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V_1 / n_1 = V_2 / n_2 - isolate V_2,

V_2 = V_1 n_2 / n_1 = 1.50 L * 2.5 mol / 3.00 mol = ( 1.5 * 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0
3 years ago
Look at the image below. What is the ratio of the formula shown? *
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The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres
Dima020 [189]

Answer:

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures  of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as K_{p}

2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)

Partial pressures at equilibrium:

p^o_{H_2O}=0.070 atm

p^o_{H_2}=0.0035 atm

p^o_{O_2}=0.0025 atm

The equilibrium constant in terms of pressures is given as:

K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}

K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

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3 years ago
Electrons must be able to flow through a material in order for the material to conduct
djverab [1.8K]

The molecular structure of the solids has lower ability to conduct electricity due to tight holding by nucleus.

<h3>Why molecular solids are poor conductors?</h3>

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Learn more about electricity here: brainly.com/question/25144822

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