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3 years ago

Which of the following ions is in the lowest oxidation state?

Chemistry

2 answers:

KATRIN_1 [288]3 years ago

5 0

Answer:

C. Fe in Fe₂O₃

Explanation:

The sum of the oxidations states times the atomicity is equal to the charge of the molecule.

2.H + 1.P + 4.O = -1

2.(1+) + 1.P + 4.(2-) = -1

P = +5

2.Cr + 7.O = -2

2.Cr + 7.(-2) = -2

2.Cr = 12

Cr = +6

2.Fe + 3.O = 0

2.Fe + 3.(-2) = 0

2.Fe = 6

Fe = +3

Fe has the lowest oxidation state (+3).

vekshin13 years ago

4 0

Answer:

the answer is c :) hope this helps buddy:))

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Valentin [98]

Answer: a) $[OH^-]=1.09\times 10^{-13}$ and pH = 1.04

b) $[H^+]=1.02\times 10^{-11}$ and $pH=10.99$

c) $[H^+]=7.08\times 10^{-11}$ and $[OH^-]=1.41\times 10^{-4}$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

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$pH+pOH=14$

a) $[H^+]=0.090M$

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$[OH^-]=1.09\times 10^{-13}$

b) $[OH^-]=0.00098M$

$pOH=-\log [0.00098]=3.01$

$pH=14-3.01=10.99$

$10.99=-log[H^+]$

$[H^+]=1.02\times 10^{-11}$

c) $pH=10.15$

$10.15=-\log [H^+]$

$[H^+]=7.08\times 10^{-11}$

$pOH=14-10.15=3.85$

$3.85=-log[OH^-]$

$[OH^-]=1.41\times 10^{-4}$

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3 years ago

A student measures the absorbance of a sample of red dye #3 using a spectrophotometer. If the absorbance is measured as 0.468, w

Gre4nikov [31]

Answer:

5.88 μM is the concentration of red dye in the sample.

Explanation:

Absorbance is defined s capacity of a substance to absorb a light of a specified wavelength.It is calculated by using Beer-Lambert Law:

$A=\epsilon lc$

A = absorbance

$\epsilon$ = Molar absorptivity

c = concentration

l = Length of the solution through which light passes

Given, A = 0.468, l = d = 1.00 cm,c = ?

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$A=\epsilon lc$

$0.468=7.96\times 10^4 M^{-1} cm^{-1}\times 1.00 cm\times c$

$c=5.8793\times 10^{-6} mol/L=5.8793 mol/(\mu L)\approx 5.88mol/(\mu L)$

( $1 L= 1,000,000 \mu L$ )

5.88 μM is the concentration of red dye in the sample.

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Answer:

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