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3 years ago

=

Mathematics

1 answer:

Savatey [412]3 years ago

4 0

Answer: 8 hours

Step-by-step explanation: First, find the unit rate. For one hour of work, she earns 0.05263157894. Multiply this number 152.

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Solve <br> −2( x+2)−7=−3(x+5) for x

Ghella [55]

Answer:

x= 9

Step-by-step explanation:

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3 years ago

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I need help plss its hard for me pls help and show the WORK plsss

My name is Ann [436]

Is there a picture of the question?

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2 years ago

Harrison rode his bike 6/10 Of a mile to the park shade the model then write 6/10 as a decimal to show how far Harrison rode his

alexira [117]

6/10 as a decimal would be 0.6

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3 years ago

Do i need to flip the reciprocal please explain your answer<br> 2y/2 < 10/2

saul85 [17]

Answer:

$\displaystyle \large \boxed{y < 5}$

Step-by-step explanation:

We are given the Inequality:

$\displaystyle \large{ \frac{2y}{2} < \frac{10}{2} }$

First, we can simplify the expression. On the left side of Inequality, we can cancel 2; on the right side, we can cancel 2 out as well.

Simply, division!

$\displaystyle \large{ \frac{ \cancel{2}y}{ \cancel{2}} < \frac{ \cancel{10}}{ \cancel{2} }}$

2 divides 2 is 1; 2 divides 10 is 5.

$\displaystyle \large{ \frac{1y}{1} < \frac{ 5}{ 1}}$

Generally, it is not recommended to write 1 beside the variable nor write 1 as a denominator.

Simplify the expression:-

$\displaystyle \large{ y < 5}$

Therefore, the value of y is less than 5.

Let me know if you have any questions after reading the explanation!

7 0

2 years ago

An average computer mouse inspector can inspect 50 mice per hour. The 48 computer mice inspectors at a particular factory can on

Ronch [10]

Answer: C. Yes, because -2.77 falls in the critical region .

Step-by-step explanation:

Let $\mu$ be the population mean .

As per given , we have

$H_0:\mu=50\\\\ H_a: \mu$

Since the alternative hypothesis is left-tailed and population standard deviation is not given , so we need to perform a left-tailed t-test.

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

Also, it is given that ,

n= 48

$\overline{x}=46$

s= 10

$t=\dfrac{46-50}{\dfrac{10}{\sqrt{48}}}=\dfrac{-4}{\dfrac{10}{6.93}}\\\\=\dfrac{-4}{1.443}\approx-2.77$

Degree of freedom = df = n-1= 47

Using t-distribution , we have

Critical value = $t_{\alpha,df}=t_{0.025,47}=2.0117$

Since, the absolute t-value (|-2.77|=2.77) is greater than the critical value.

So , we reject the null hypothesis.

i.e. -2.77 falls in the critical region.

[Critical region is the region of values that associates with the rejection of the null hypothesis at a given probability level.]

Conclusion : We have sufficient evidence to support the claim that these inspectors are slower than average.

Hence, the correct answer is C. Yes, because -2.77 falls in the critical region

4 0

3 years ago