1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Musya8 [376]
3 years ago
12

A mountain climber ascends a mountain to its peak. The peak is 12,470 ft above sea level. The climber then descends 80 ft to mee

t a fellow climber. Find the climber's elevation above sea level after meeting the other climber. A. -12,390 ft. B. 12,550 ft. C. 11,670 ft. D. 12,930 ft
Physics
1 answer:
o-na [289]3 years ago
8 0
The answer is 12,390 ft.

At first, a climber is at 12,470 <span>ft above sea level. But then, he goes down 80 ft to meet a fellow climber. So, this simply needs to be distracted:
12,470 ft - 80 ft = 12,390 ft
This is the elevation </span>above sea level at which he meet the other climber.
You might be interested in
A very rare type of lightning that appears as a reddish-colored sphere is called _____.
torisob [31]
<span>A very rare type of lightning that appears as a reddish-colored sphere is called   </span>A + Ball Lightening
5 0
3 years ago
17 of 24 Constants In an experiment to simulate conditions within an automobile engine, 0.165 mol of air at a temperature of 700
steposvetlana [31]

Answer:

a. T₂ = 901.43 ° K

b. T₂ = 843.85 ° K

Explanation:

Given

η = 0.165 mol , Q = 690 J , V = 280 cm³ , P = 3.40 x 10 ⁶ Pa , T₁ = 700 ° K

Using the equation that describe the experiment of heat

Q = η * Cv * ΔT

a.

Nitrogen   Cv =  20.76 J / mol ° K  

ΔT = T₂ - T₁

T₂ = [ Q / ( η * Cv) ] + T₁

T₂ = [ 690 J / ( 0.165 mol * 20.76 J / mol ° K ) ] + 700 ° K

T₂ = 901.43 ° K

b.

Nitrogen   Cp = 29.07 J / mol ° K

T₂ = [ Q / ( η * Cv) ] + T₁

T₂ = [ 690 J / ( 0.165 mol * 29.07 J / mol ° K ) ] + 700 ° K

T₂ = 843.85 ° K

5 0
3 years ago
What are the basic si units for the wavelength of light?
noname [10]

Answer:

Meter (m)

Explanation:

The wavelenght of a light wave is a measure of the distance between two successive crests (or two successive troughs) of a light wave.

Since the SI units for the distance is the meter (m), then the SI unit for the wavelength is also the meter (m).

Wavelength is related to the frequency of the light wave by:

\lambda=\frac{c}{f}

where

c is the speed of light

f is the frequency of the light

7 0
3 years ago
The distance covered by a car at a time, t is given by x = 20t + 6t4, calculate
Anni [7]

Answer:

(i) v = 44 m/s

(ii) a = 72 m/s^2

Explanation:

You have the following equation for the potion of a car:

x=20t+6t^4

(i) The instantaneous velocity is the derivative of x in time:

\frac{dx}{dt}=20+(6)(4)t^3=20+24t^3

for t = 1 is:

v(t=1)=\frac{dx}{dt}=20+24(1)^3=44m/s

(ii) The instantaneous acceleration is the derivative of the velocity:

\frac{dv}{dt}=24(3)t^2=72t^2

for t = 1

a(t=1)=\frac{dv}{dt}=72(1)^2=72m/s^2

8 0
4 years ago
A car of mass 1000 kg is moving at 25 m/s. It collides with a car of mass 1200 kg moving at 30 m/s. When the cars collide, they
Alinara [238K]

Answer:

The total momentum of the cars before the collision is 61,000 kg.m/s

The total momentum of the cars after the collision is 61,000 kg.m/s

The velocity of the cars after the collision is 27.727 m/s

Explanation:

Given;

mass of the first car, m₁ = 1000 kg

initial velocity of the car, u₁ = 25 m/s

mass of the second car, m₂ = 1200 kg

initial velocity of the second car, u₂ = 30 m/s

The common velocity of the cars after collision = v

The total momentum of the cars before collision is calculated as;

P₁ = m₁u₁  +  m₂u₂

P₁ = (1000 x 25)  +  (1200 x 30)

P₁ = 61,000 kg.m/s

The total momentum of the cars after collision is calculated as;

P₂ = m₁v + m₂v

where;

v    is the common velocities of the cars after collision since they stick together.

P₂ = v(m₁ + m₂)

To determine "v" apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁  +  m₂u₂  = v(m₁  + m₂)

(1000 x 25)  +  (1200 x 30) = v(1000 + 1200)

61,000 = 2,200v

v = 61,000/2,200

v = 27.727 m/s

The total momentum after collsion = v(m₁ + m₂)

                                                         = 27.727(1000 + 1200)

                                                          = 61,000 kg.m/s

Thus, momentum before and after collsion are equal.

8 0
3 years ago
Other questions:
  • Find the magnitude of the electric field at a point midway between two charges +13.6 x 10-9 C and +61.0 x 109 C separated by a d
    6·1 answer
  • 1. Oxygenated blood is necessary for proper bodily functions. If there isn’t enough oxygen in a person’s blood they can become l
    8·2 answers
  • A merry-go-round with a a radius of R = 1.63 m and moment of inertia I = 196 kg-m2 is spinning with an initial angular speed of
    6·1 answer
  • How many forces are acting on a stationary raft floating in a swimming pool A1 B2 or C3
    14·1 answer
  • Anosh gets two bulbs of the following power ratings to add ambience to his study desk.
    6·1 answer
  • Interpret the trend in the data shown in the form of table.
    12·1 answer
  • Use the diagram below to answer question #4.
    14·1 answer
  • Which two statements about kinetic energy are true
    6·1 answer
  • What is the medium through which sound travels inside a bird’s body? (HINT: three-letter word)
    13·1 answer
  • 63 J of heat are added to a closed system. The initial energy of the system is 58J, and the final internal energy is 93J. How mu
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!