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Musya8 [376]
3 years ago
12

A mountain climber ascends a mountain to its peak. The peak is 12,470 ft above sea level. The climber then descends 80 ft to mee

t a fellow climber. Find the climber's elevation above sea level after meeting the other climber. A. -12,390 ft. B. 12,550 ft. C. 11,670 ft. D. 12,930 ft
Physics
1 answer:
o-na [289]3 years ago
8 0
The answer is 12,390 ft.

At first, a climber is at 12,470 <span>ft above sea level. But then, he goes down 80 ft to meet a fellow climber. So, this simply needs to be distracted:
12,470 ft - 80 ft = 12,390 ft
This is the elevation </span>above sea level at which he meet the other climber.
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Taking east as positive direction and west as negative direction, we have:

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Answer:

\huge\boxed{\sf P.E. = 240\ MJ}

\huge\boxed{\sf K.E. = 19.6\ MJ}

Explanation:

<u>Given:</u>

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Speed = v = 14 m/s

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<u>Required:</u>

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K.E. = (100000)(196)

K.E. = 19,600,000 Joules

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