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AlladinOne [14]
3 years ago
9

Can a vector have a component greater than its magnitude

Physics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

NO

Explanation:

The components of a vector can not have a magnitude greater than the vector itself.The magnitude of a component is always lesser than vector because the magnitude is a product of the vector and cos Ф where the value of cos Ф , x,  is -1<x<1. Additionally, applying the Pythagorean relationship, you expect the sum of squares of the components to equal the square of the magnitude of the vectors.However, there is a situation where a component of a vector has a magnitude which equals the magnitude of the vector.

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Assume that a friend hands you a 10-newton box to hold for her. If you hold the box without moving it at a height of 10 meters a
malfutka [58]

Answer:

100 Joules

Explanation:

Applying,

W = mgh................... Equation 1

Where W = workdone to hold the box above the ground, mg = weight of the box, h = height of the box.

From the question,

Given: mg = 10 newtons, h = 10 meters.

Substitute these values into equation 1

W = 10×10

W = 100 Joules.

Hence the amount of workdone is 100 Joules

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3 years ago
2 What can you Infer about this source of electricity?
anzhelika [568]

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Explanation:

6 0
3 years ago
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MA_775_DIABLO [31]
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3 years ago
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In the parts that follow select whether the number presented in statement A is greater than, less than, or equal to the number p
OleMash [197]

Answer:

1)   A> B, 2)  A = B,  3)    A> B

Explanation:

When a figure is given the number of significant figures to determine the precision or uncertainty the number

1) the uncertainty in the number with three significant figures is less than the number with two significant figures

statement A 2.6

statement B 2.57

        A> B

2) decalration A

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with two figures it remains

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statement B

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3) for the product the result is with the number that has the least significant figures

statement A

rectangles area

   2.536 * 1.4 = 3.6

  statement B

    2.536 * 1.41 = 3.58

          A> B

7 0
3 years ago
the potential energy of a 40kg cannon ball is 14000j. How high was the cannon ball to have this much potential energy?
noname [10]
We will use the formula p = mgh p is potential energy. m is mass of object in kg g is acceleration due to gravity (9.8m/s²) h is height of the objects displacement in meters. p = mgh → mgh = p → h = p / mg p is 14000j, m is 40kg and g is 9.8 m/s² h = 14000 / 40 × 9.8 → h = 1400 / 392 → h = 35.7 Therefore , the cannonball was 35.7 meters high .
7 0
4 years ago
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