C
Pure water is at 7, and the bases are above 7 and the acids are below 7.
The component parts of a compound that can ever exist and still retain the chemical properties of that compound
Explanation:
The oxidation number of chlorine can be -1, 0, +1, +3, +4, +5, or +7, depending on the substance containing the chlorine. The most common oxidation numbers are -1 (as in HCl and NaCl ) and 0 (as in Cl2 ).
2 mole Na needs 1 mole Cl2
4 mole Na = 2 mole Cl2
Answer:
H₂S + Cl₂ —> S + 2HCl
Explanation:
? + Cl₂ —> S + 2HCl
To balance the equation above, we must recognise what atoms are present in the products.
The products contains S, H and Cl.
Thus, S, H and Cl must also be present in the reactants.
Considering the equation given above, we can see clearly that H and S is missing in the reactants.
H and S together as a compound is expressed as H₂S.
Now, we shall input H₂S into the equation to obtain the complete equation. This is illustrated below:
? + Cl₂ —> S + 2HCl
H₂S + Cl₂ —> S + 2HCl
Next, we shall verify to see if the equation is balanced.
There are 2 atoms of H on both sides of the equation.
There are 2 atoms of Cl on both sides of the equation.
1 atom of S exist on both sides of the equation.
Thus, the equation is balanced.
