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podryga [215]
2 years ago
11

Consider the mass and velocity values of Objects A and B below.

Physics
1 answer:
777dan777 [17]2 years ago
8 0

Answer:

the same

Explanation:

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Which of these accurately describes the products of a reaction?
stiv31 [10]
The one that accurately describes the products of a reaction is : B. new substances that are present at the end of a reaction
For example the process of photosynthesis transform CO2 and other nutrients into O2 and H2O

hope this helps
3 0
2 years ago
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Which of the following is used in Sonata II's prepared piano?
Delvig [45]
It is C. Copper wire.
8 0
3 years ago
A force of 3kN acts on a car to make it accelerate by 1.5m/s/s. What is the mass of the car?
Masja [62]

Answer:

2

Explanation:

To find force it's force = mass times acceleration so to find mass you would divide force by acceleration

5 0
3 years ago
If the opening to the harbor acts just like a single-slit which diffracts the ocean waves entering it, what is the largest angle
soldi70 [24.7K]

Answer:

The angle that the wave would be \theta = sin ^{-1}\frac{2 \lambda}{D}

Explanation:

From the question we are told that  the  opening to  the  harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the  on at angle greater than the diffraction first minimum would be slightly affected

  The minimum is as a result of destructive interference

       And for single-slit this is mathematically represented as

               D sin \ \theta =m \lambda

where D is the slit with

          \theta is the angle relative to the original direction of the wave

         m is the order of the minimum j

        \lambda is the wavelength

Now since in the question we are told to obtain the largest angle at which the boat would be safe

      And the both is safe at the angle equal to the second minimum then

    The the angle is evaluated as

           \theta = sin ^{-1}[\frac{m\lambda}{D} ]

Since for second minimum m= 2

The  equation becomes

               \theta = \frac{2 \lambda}{D}

3 0
2 years ago
A bucket of water of mass 10 kg is pulled at constant velocity up to a platform 30 meters above the ground. This takes 10 minute
Rudik [331]

Answer:

W = 2352 J

Explanation:

Given that:

  • mass of the bucket, M = 10 kg
  • velocity of pulling the bucket, v = 3m.min^{-1}
  • height of the platform, h = 30 m
  • time taken, t = 10 min
  • rate of loss of water-mass, m = 0.4 kg.min^{-1}

Here, according to the given situation the bucket moves at the rate,

v=3 m.min^{-1}

The mass varies with the time as,

M=(10-0.4t) kg

Consider the time interval between t and t + ∆t. During this time the bucket moves a distance

∆x =  3∆t meters

So, during this interval change in work done,

∆W = m.g∆x

<u>For work calculation:</u>

W=\int_{0}^{10} [(10-0.4t).g\times 3] dt

W= 3\times 9.8\times [10t-\frac{0.4t^{2}}{2}]^{10}_{0}

W= 2352 J

5 0
3 years ago
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