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faltersainse [42]
4 years ago
5

According to the condensation theory, the most important factor for the formation of our planets was _____. the gravitational pu

ll of the Sun the interstellar dust attracting heat away from the protosun the process of nuclear fusion the nebular cloud condensing
Physics
2 answers:
mart [117]4 years ago
5 0

According to the condensation theory, the most important factor for the formation of our planets was "the interstellar dust attracting heat away from the protosun".


Condensation is the procedure by which water particles noticeable all around bunch together and shape fluid water. This is regularly observed outwardly of cold glasses. This idea additionally identifies with the solar system.

The condensation theory of the solar system expresses that our solar system, and perhaps all other galaxies, were shaped from a cloud of residue and gas that consolidated into strong issue. Space experts trust that the littlest grains of residue in our cloud applied a draw on the gas about it, 'consolidating' into bigger and bigger bits of issue, similarly as a snowball moving downhill will become bigger and bigger. In the long run, the gravitational draw of these residue atoms was sufficiently solid that they started to pull in each other, developing into greater and greater clusters that had more grounded gravitational pulls. In the long run, these bunches of residue and gas from the cloud frame a star, and potentially planets, space rocks, and comets turning about the star.

Mandarinka [93]4 years ago
3 0
It was the gravitational pull of the sun
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The electric field in a region of space has the components Ey = Ez = 0 and Ex = (4.00 N/C · m) x. Point A is on the y axis at y
igor_vitrenko [27]

Answer:

   V_{b}-V_{a} = -38.72

Explanation:

Consider the axis diagram attached.

Given:

                                        Ey = Ez = 0

                                       Eₓ = - 4x N/C · m

Since electric field is in x direction, potential difference would be:

              V_{b} - V_{a} =-\int\limits^{4.40}_{0} {E_{x} } \, dx

Here we integrate between limits 0 and 4.40 which is distance between A and B along x-axis.  

              V_{b} - V_{a} = -4 \left[\begin{array}{ccc}\frac{x^{2} }{2} \end{array}\right]^{4.40}_{0}

                       V_{b}-V_{a} = -4 (9.68)\\V_{b}-V_{a} = -38.72

5 0
3 years ago
Two football players run towards each other along a straight path in Penrith Park in the clash between the Melbourne storms and
Agata [3.3K]

Answer:

a) v = 0.4799 m / s,  b)  K₀ = 1600.92 J,    K_f = 5.46 J

Explanation:

a) How the two players collide this is a momentum conservation exercise. Let's define a system formed by the two players, so that the forces during the collision are internal and also the system is isolated, so the moment is conserved.

Initial instant. Before the crash

        p₀ = m v₁ + M v₂

where m = 95 kg and his velocity is v₁ = -3.75 m / s, the other player's data is M = 111 kg with velocity v₂ = 4.10 m / s, we have selected the direction of this player as positive

Final moment. After the crash

       p_f = (m + M) v

as the system is isolated, the moment is preserved

       p₀ = p_f

       m v₁ + M v₂ = (m + M) v

       v =\frac{m v_1 + M v_2}{m+M}

let's calculate

        v = \frac{ -95 \ 3.75 \ + 111 \ 4.10}{95+111}

        v = 0.4799 m / s

b) let's find the initial kinetic energy of the system

         K₀ = ½ m v1 ^ 2 + ½ M v2 ^ 2

         K₀ = ½ 95 3.75 ^ 2 + ½ 111 4.10 ^ 2

         K₀ = 1600.92 J

the final kinetic energy

         K_f = ½ (m + M) v ^ 2

         k_f = ½ (95 + 111) 0.4799 ^ 2

         K_f = 5.46 J

3 0
3 years ago
A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is
Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration a_{c} is given by the following equation:  

a_{c}=\frac{V^{2}}{r} (1)

Where:  

a_{c}=17 m/s^{2} is the <u>centripetal acceleration</u>

V is the<u> tangential speed</u>

r=12 m is the <u>radius</u> of the circle

Isolating V from (1):

V=\sqrt{a_{c}r} (2)

V=\sqrt{(17 m/s^{2})(12 m)}

<u />

Finally:

V=14.28 m/s This is the girl's tangential speed

3 0
3 years ago
What is total mechanical energy?
ollegr [7]

Answer:

is the energy possessed by an object due to either its motion or its stored energy of position. The total amount of mechanical energy is merely the sum of these two forms of energy. And finally, an object with mechanical energy is able to do work on another object.

Explanation:

5 0
3 years ago
How much electrical energy is used by a 350 W television that is operating for
Igoryamba

Answer:

525,000J

Explanation:

Power = work/time

Given

Power = 350 watts

Time = 25 mins = 25 x 60 = 1500 secs

Therefore

350 = work/1500

Cross multiply

Work = 350 x 1500

Work = 525,000J

4 0
3 years ago
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