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emmainna [20.7K]
4 years ago
5

At what speed, in meters per second, does the Moon recoil after the perfectly inelastic collision? The mass of the Moon is 7.36

× 1022 kg?

Chemistry
2 answers:
RUDIKE [14]4 years ago
3 0

Answer:The moon will recoil at 1.019×10^-6m/s

Explanation:To determine the recoil velocity of the moon after the inelastic collisions

Given:

Mass of moon=7.36×10^22kg=m1

Mass of asteroids = 5×10^12=m2

Initial velocity of moon =0

Initial velocity of asteroids =15km/s=15000m/s

The law of conservation of momentum is given as

M1v1 + m2v2 =(m1+m2)v'

O + m2v2= (m1 +m2)v'

V'=m2v2/(m1+m2)

V'=(5×10^22)×15000/(7.36×10^22)+(5×10^12)

V'=1.019×10^-6m/s

Romashka [77]4 years ago
3 0

Answer:

The moon will recoil at the speed of 1.019×10^-6 m/s the whole mass

Explanation:

Mass of moon=7.36×10^22kg=m1

Mass of asteroids = 5×10^12=m2

Initial velocity of moon =0

Initial velocity of asteroids =15km/s=15000m/s

The law of conservation of momentum is given as

M1v1 + m2v2 =(m1+m2)v'

0 + m2v2= (m1 +m2)v'

V'=m2v2/(m1+m2)

V'=(5×10^22)×15000/(7.36×10^22)+(5×10^12)

V'=1.019×10^-6m/s

Please find the attached picture to get the full explanation.

I hope these helps, kindly give brainliest if it does

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