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bagirrra123 [75]
3 years ago
5

Which conditions will increase the rate of a chemical reaction?

Chemistry
1 answer:
Nata [24]3 years ago
4 0

Answer:

je suis nulle en franglais

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Calculate the percent yield if 52.9 g of ethanol reacts to produce 26.7 g of ether.
blagie [28]

Answer:

The % yield is 62.7 %

Explanation:

<u>Step 1:</u> the balanced equation

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

<u>Step 2:</u> Data given

mass of ethanol = 52.9 grams

molar mass of ethanol = 46.07 g/mol

mass of ether = 26.7 grams

Molar mass of ether = 74.12 g/mol

<u>Step 3:</u> Calculate moles of ethanol

Number of moles = Mass / molar mass

Moles of ethanol = 52.9 grams / 46.07 g/mol

Moles of ethanol = 1.15 moles

<u>Step 4: </u>Calculate moles of ether

For 2 moles of ethanol consumed, we have 1 mole of ether produced

For 1.15 moles of ethanol consumed, we have 1.15/2 = 0.575 moles of ether produced

<u>Step 5:</u> Calculate mass of ether

Mass = moles * Molar mass

Mass ether = 0.575 moles * 74.12 g/mol = 42.62 grams = theoretical yield

<u>Step 6:</u> Calculate % yield

% yield = (26.7 / 42.62) * 100 = 62.7%

The % yield is 62.7 %

6 0
4 years ago
A plasma that has particles that never collide frequently enough to exchange kinetic energy and never reach a temperature equal
Stels [109]

Answer:

For comprehension, the question is written properly with options attached below:

plasma that has particles that never collide frequently enough to exchange kinetic energy and never reach a temperature equal to the surroundings is categorized as:

A. a thermal plasma.

B. ionized plasma.

C. low density plasma

D. nonthermal plasma.

The correct answer to the question above is "Option D (nonthermal plasma.)"

Explanation:

Plasma, for example radiant sun are state of matter made up of atoms where the ions move freely, there are composed of photons and free electrons but the positive and negative ions are equal creating a swirling gas of positive ions and negative electron and they are also good conductors of electricity as their charged particles move.

Unlike thermal plasmas that ensure their temperature is equal to their surroundings, non-thermal plasma, is not in equilibrium with its surrounding., in other words, non-thermal plasma never reaches temperature that is equal to their surroundings. They can be formed by electrifying electromagnetic waves.

6 0
4 years ago
Read 2 more answers
10) an object has mass of 50g 500mg and 0.1g. express the total mass of the object in grams
Pavel [41]
500 mg in g :

1 g ----------- 1000 mg
? -------------- 500 mg

500 x 1 / 1000 => 0.5 g

total mass:

50 g + 0.5 g + 0.1 g => 50.6 g

hope this helps!
8 0
3 years ago
Which chemical equation correctly represents the formation of water and carbon dioxide from the decomposition of carbonic acid i
finlep [7]

Carbonic acid refers to a weak inorganic acid, which is also known as the solution of carbon dioxide in water. It only prevails as a solution and is also known as the aerial acid, acid of air, dihydrogen carbonate, or carbon dioxide solution. It is most familiar as a constituent of the majority of the aerated drinks like soft drinks and sodas.  

The carbonic acid's chemical formula is H₂CO₃. Its decomposition to water and carbon dioxide is shown by the equation:  

H₂CO₃ (g) = H₂O (l) + CO₂ (g)


5 0
4 years ago
g An oxidized silicon (111) wafer has an initial field oxide thickness of d0. Wet oxidation at 950 °C is then used to grow a thi
77julia77 [94]

Answer:

Explanation:

From the information given:

oxidation of oxidized solution takes place at 950° C

For wet oxidation:

The linear and parabolic coefficient can be computed as:

\dfrac{B}{B/A} = D_o \ exp \Big [\dfrac{-\varepsilon a}{k_BT} \Big]

Using D_o and E_a values obtained from the graph:

Thus;

\dfrac{B}{A} = 1.63 \times 10^8 exp \Big [ \dfrac{-2.05}{8.617 \times 10^{_-5}\times 1173}\Big] \\ \\ = 0.2535 \ \ \mu m/hr

B= 386 \  exp \Big [-\dfrac{0.78}{8.617 \times 10^{-3} \times 1173} \Big] \\ \\  = 0.1719 \ \mu m^2/hr

So, the initial time required to grow oxidation is expressed as:

t_{ox} = \dfrac{x}{B/A}+ \dfrac{x^2}{B} - t_o (initial)

where; \\ \\ t_{ox} = 2 \ hrs;\\ \\ x = 0.5 \\ \\ B/A = 0.2535 \\ \\  B = 0.1719

∴

2= \dfrac{0.5}{0.2535}+ \dfrac{0.5^2}{0.1719} - t_o (initial)

2 = 3.4267 - t_o (initial) \\ \\ t_o(initial) = 3.4267 - 2  \\ \\ t_o(initial) = 1.4267 \ hr

NOW;

1.4267 = \dfrac{d_o}{0.2535} + \dfrac{d_o^2}{0.1719} \\ \\  1.4267 = 3.9448 \ d_o + 5.8173 \ d_o^2 \\ \\ d_o^2 + 0.6781 \ d_o = 0.2453

d_o = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}

d_o = \dfrac{-(0.6781) \pm \sqrt{(0.6781)^2-4(1)(-0.245)}}{2(10)}

d_o = \dfrac{-(0.6781) \pm \sqrt{0.45981961+0.98}}{20}

d_o = \dfrac{-(0.6781) \pm \sqrt{1.43981961}}{20}

d_o = \dfrac{-(0.6781) + \sqrt{1.43981961}}{20} \ OR \   \dfrac{-(0.6781) - \sqrt{1.43981961}}{20}

d_o =0.02609 \ OR \   -0.0939

Thus; since we will consider the positive sign, the initial thickness d_o is ;

≅ 0.261 μm

3 0
3 years ago
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