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nlexa [21]
3 years ago
14

[ 1.3 ] What is the concentration (%) of solute in the RBC (i.e., what is the concentration of all solute molecules combined?) A

s before, show your calculations. You might find it helpful to refer to the example calculation in the previous exercise.
Chemistry
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

0.9%

Explanation:

At the instance where you add RBCs to a solution of 0.9% NaCl, they will maintain their shape as well as their size, this is simply to indicate an equilibrium. That entails that the solution is isotonic to the RBCs. This must mean that the concentration of solutes on each side must be equal otherwise osmotic pressure would force water either in or out of the membrane. Therefore, one can also safely assume that RBC's also have a solute concentration of 0.9%.

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the radius of the Sun is approximately 696,000 kilometers, while bacterial cells are as small as 1.9 × 10-4 millimeters. Express
Mazyrski [523]

Explanation;

Writing scientific notation :

  • Move the decimal to the left side until single digit of number remains before the decimal.
  • Then we will count the number of times we moved the decimal. Write this number as the exponential power of number '10'.
  • For Example: 2894.55=2.89455\times 10^{3}

Radius of the sun = 696,000.0 kilometer

1 km=10^3 m

Radius of the sun can also be written as = 6.96\times 10^{5} km=6.96\times 10^{5}\times 10^3 m=6.96\times 10^{8} meter

Size of bacterial cell = 1.9\times 10^{-4} millimeter

1 mm=1\times 10^{-3} m

Size of bacterial cell can also be written as = 1.9\times 10^{-4}\times 10^{-3} m=1.9\times 10^{-7} meter

4 0
3 years ago
You draw back on the piston of a pump and the volume of air in the pump doubles. Which of the following happens?
ohaa [14]

Answer: The correct answer is Option C.

Explanation:

We are given a piston of a pump, which means that there is no loss of the air. and there is a change in pressure and volume but temperature of the system remains constant.

As, the pressure of the system increases, there will be more number of particles. So, the number of collisions per unit area will increase.

\text{Number of collisions}\propto \text{Pressure}

But in the question, volume gets doubled. So, the pressure will be determined by using Boyle's Law:

P\propto \frac{1}{V}

V_2\rightarrow 2V_1

where, V_1\text{ and }V_2 are the initial and final volume respectively.

Putting the change in volume in above equation, we get:

P_2=\frac{1}{2V_1}\\\\P_2=\frac{1}{2}P_1

where, P_1\text{ and }P_2 are the initial and final pressure respectively.

As, the pressure is reduced to half of the initial pressure. So, the number of collisions per unit area will also be reduced to one-half.

Hence, the correct answer is Option C.

5 0
3 years ago
Read 2 more answers
What product of the krebs cycle is considered a waste product of the reaction?
Rufina [12.5K]
The answer is carbon dioxide 
5 0
3 years ago
Write the net ionic equation describing the reaction between aluminum metal and Fe3+ ions in solution that produces dissolved Al
leonid [27]

Answer:

Al (s) + 3Fe3+ (aq) ---> Al3+ (aq) + 3Fe2+(aq)

Explanation:

atoms become positive (or less negative) ions when they lose electrons. They become negative (or less positive) ions when they gain electrons, since each electron (e-) has a charge of -1.

So, since Al changes to Al3+ which is positive, it loses electrons. And when Fe3+ changes to Fe2+, it becomes less positive, so it gained electrons.

Now, write the half (balanced) equations:

Al ---> Al3+ + 3e-

Fe3+ + e- ----> Fe2+

To combine both equations, we have to eliminate electrons. To do so, make sure both half equations have the same no. of electrons. We can multiply the equation of Fe by 3 so that it has 3 electrons.

3Fe3+ + 3e- ----> 3Fe2+

Finally, we can combine both equations (remember to eliminate the electrons).

Al (s) + 3Fe3+ (aq) ---> Al3+ (aq) + 3Fe2+(aq)

Check to see if both sides of the equation have equal charges. Ions always have an aqueous state.

5 0
3 years ago
2CuO+2NH3------ 3Cu + 3H2O+ N2. Given that the relative molecular mass of copper oxide is 80, what volume of ammonia is required
Pani-rosa [81]

Volume of Ammonia(NH₃) = 22.4 L

<h3>Further explanation</h3>

Given

Reaction

3CuO+2NH₃⇒ 3Cu + 3H₂O+ N₂

<em>In the problem, the CuO coefficient should be 3 not 2</em>

M CuO = 80

mass CuO = 120 g

Required

The volume of NH₃

Solution

mol CuO :

\tt mol=\dfrac{mass}{M}\\\\mol=\frac{120}{80}\\\\mol=1.5

From the equation, mol ratio CuO : NH₃ = 3 : 2, so mol NH₃=

\tt \dfrac{2}{3}\times 1.5=1~mol

Assume at STP(0 °C, 1 atm) ⇒1 mol = 22.4 L, then volume of NH₃=22.4 L

4 0
3 years ago
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