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ruslelena [56]
3 years ago
7

Determine the second derivative of y=cosxtanx. Thanks :)

Mathematics
1 answer:
devlian [24]3 years ago
6 0
f(x)=cosxtanx\\\\(cosxtanx)'=\left(cosx\cdot\frac{sinx}{cosx}\right)'=(sinx)'=cosx\\\\(cosx)'=-sinx\\\\f''(x)=-sinx\\\\\frac{\delta^2 f}{\delta x^2}=-sinx
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Площадь параллелограмма сторона которого равна 4,7 см а проведённая к ней высота 3,1​
Finger [1]

Answer:

im sorry but i dont understand

5 0
3 years ago
Please help me thank you!
sergiy2304 [10]

Answer:

The equation of the line that passes through the points

(5,2) and (-5,6)

is

y=-2/5x+4

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(5,2) and (-5,6).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (5,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=5 and y1=2.

Also, let's call the second point you gave, (-5,6), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=6.

Now, just plug the numbers into the formula for m above, like this:

m= 6 - 2/-5 - 5 or m= 4-10 or m=-2/5

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-2/5x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(5,2). When x of the line is 5, y of the line must be 2.

(-5,6). When x of the line is -5, y of the line must be 6.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-2/5x+b. b is what we want, the -2/5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (5,2) and (-5,6).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(5,2). y=mx+b or 2=-2/5 × 5+b, or solving for b: b=2-(-2/5)(5). b=4.

(-5,6). y=mx+b or 6=-2/5 × -5+b, or solving for b: b=6-(-2/5)(-5). b=4.

3 0
2 years ago
Base:9.44 area=70.8 WHAT IS THE HIEGHT
Harlamova29_29 [7]
Divide

a = b * h
we know the base and area, not height

h = a/b
h = 70.8/9.44
h = 7.5

Your height is 7.5 units 
6 0
3 years ago
What is Pythagoras theorem
nikitadnepr [17]
Its an equation that helps you find the hypotenuse of a right triangle 

c= √( a²+b²)


4 0
3 years ago
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Answer:

<h2> A Po </h2>
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