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ratelena [41]
3 years ago
13

Solids we need to live

Chemistry
1 answer:
gogolik [260]3 years ago
6 0
Foods are a solid we need to survive
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? Question
mr_godi [17]

A is the answer

In an ozone molecule, the three atoms must be connected, so there must at least be a single bond between them. Place

dots in pairs around the oxygen atoms until each oxygen atom has eight valence electrons, starting with the atoms on the

outside and doing the central atom last if there are enough. Do not exceed the total number of valence electrons

identified in part A. Remember that the dashes between the oxygen atoms, which represent single bonds, each indicate

the presence of two valence electrons

6 0
3 years ago
Which of the following is not the same as 2.97 milligrams? 0.0000297 kg, 0.00297 g, 0.297 ch
Travka [436]

the correct answer its  0.002975

4 0
4 years ago
Read 2 more answers
Which law represents a balanced chemical equation?​
Montano1993 [528]

Answer:

All chemical equations goes to the law of conservation of mass which says that matter can not be destroyed nor created which means there has to be an equal amount of atoms of each element on both sides of the equation. I hope that helps, I'm learning this as well.

8 0
3 years ago
por favor es urgente!!!!!!!!.... 1 -¿cuántos átomos- gramos de cloro hay en 88,75 g de dicho elemento? 2-¿calcular los moles de
Mamont248 [21]

Answer:

don't understand your language

6 0
3 years ago
Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. a. 0.100 mole of Ca(N
pickupchik [31]

Answer:

[Ca²⁺] = 1M

[NO₃⁻] = 2M

Explanation:

Calcium nitrate dissociates in water as follows:

Ca(NO₃)₂ ⇒ Ca²⁺ + 2NO₃⁻

The moles of Ca²⁺ can be found using the molar relationship between Ca(NO₃)₂ and Ca²⁺

(0.100mol Ca(NO₃)₂) (Ca²⁺ /Ca(NO₃)₂) = 0.100 mol Ca²⁺

The concentration of Ca²⁺  is then:

[Ca²⁺] = n/V = (0.100mol)/(100.0mL) x (1000ml)/(1L) = 1M

Similarly, moles of NO₃⁻ can be found using the molar relationship between Ca(NO₃)₂ and NO₃⁻:

(0.100mol Ca(NO₃)₂) (2NO₃⁻/Ca(NO₃)₂) = 0.200 mol NO₃⁻

The concentration of NO₃⁻ is then:

[NO₃⁻] = (0.200mol)/(100.0mL) x (1000ml)/(1L) = 2M

6 0
3 years ago
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