3.75 litres is the volume of the balloon indoors at a temperature of 25°C.
Explanation:
Data given:
initial temperature of the gas in balloon = -35°C or 238.15 K
initial volume = 3 litres
final temperature = 25 °C or 298.15 K
final volume =?
pressure remains constant
From the data given when pressure is constant Charles' law is applied.
= 
Rearranging the equation to know the final volume of the gas in balloon
V2 = 
V2 = 
V2 = 3.75 Litres
when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.
Answer:
I guess the answer is compound
Explanation:
Coz compound it is on there playing with me again Go ahead and paste it in the class
Answer: When baking soda and vinegar are combined, a new substance is produced. The carbon dioxide gas soon foams up in the mixture. Carbon dioxide, water, and sodium acetate are generated when sodium bicarbonate and acetic acid react.As Kobe adds additional baking soda and vinegar, the reaction will also become stronger.
Explanation: <em>well to be completely honest I don't see any answer choices so I'm going to assume that this is a writing question</em>
Answer: D : A is 3 : 2.
Explanation:
The law of definite proportion is being used here. The law states that a given compound always has the same proportion of its constituent elements by mass.
2a + b = c + 3d
This actually means that, two moles of “a” react with a mole of “b” to produce a mole of “c” and 3 moles of “d”
Using the concept of stoichiometry coefficients of d and a
d:a = 3:2
Answer:
V₂= 1.9 L
Explanation:
Given data:
Initial volume of gas = 2.20 L
Temperature = 30°C (30+273 = 303 K)
Initial pressure = 735.43 mmHg (735.43 /760 = 0.97 atm)
Final volume of gas = ?
Final temperature = standard = 273 K
Final pressure = standard = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.97 atm × 2.20 L × 273 K / 303 K × 1 atm
V₂= 582.58 atm .L. K / 303 k.atm
V₂= 1.9 L
