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Scilla [17]
3 years ago
9

Solve for x. 1n(5x-3)=2

Mathematics
2 answers:
fredd [130]3 years ago
5 0
So sorry about my handwriting

pav-90 [236]3 years ago
3 0

Answer: x=-1/5n+1

Step-by-step explanation:

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3 years ago
Jim has only dimes and nickels in his coin bank. He has 37 coins with a total value of $2.65.
guajiro [1.7K]

Answer:

21

Step-by-step explanation:

Let x represent the number of dimes and y represent the number of nickels.  The total number of coins is 37; this gives us the equation

x+y = 37

Each dime is worth ten cents, or 0.10, and each nickel is worth five cents, or 0.05.  The total amount of money is given by

0.10x+0.05y = 2.65

This gives us the system

\left \{ {{x+y=37} \atop {0.10x+0.05y=2.65}} \right.

To solve this, we will use substitution.  We will isolate x in the first equation:

x+y=37

Subtract y from each side:

x+y-y = 37-y

x = 37-y

Substitute this into the second equation:

0.10(37-y)+0.05y = 2.65

Using the distributive property,

0.10(37)-0.10(y)+0.05y = 2.65

3.70-0.10y+0.05y = 2.65

Combining like terms,

3.70-0.05y = 2.65

Subtract 3.70 from each side,

3.70-0.05y-3.70 = 2.65-3.70

-0.05y = -1.05

Divide both sides by -0.05:

-0.05y/-0.05 = -1.05/-0.05

y = 21

There were 21 nickels.

4 0
3 years ago
Read 2 more answers
16.8 - (-23.72)+(-31.3) = x
KatRina [158]

Let's solve  your equation step-by-step

16.8-(-23.72)-31.3=x

Step 1:simplify both sides of the equation

16.8-(-23.72)-31.3=x

16.8+23.72+-31.3=x

(16.8+23.72+-31.3)=x (combine like terms)

9.22=x

9.22=x

Step 2: flip the equation

Answer: x=9.22

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3 years ago
Can anyone help!?! I don’t understand the distance formula. Can someone pls explain it?
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Explain what? ........
5 0
3 years ago
Can anyone help me with this?<br><br> Reduce the fraction
Elden [556K]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{-20t^5u^2v^3}{48t^7u^4v}\implies \cfrac{-20}{48}\cdot \cfrac{t^5u^2v^3}{t^7u^4v^1}\implies \cfrac{-5}{12}\cdot \cfrac{v^3v^{-1}}{t^7t^{-5}u^4u^{-2}}\implies \cfrac{-5}{12}\cdot \cfrac{v^{3-1}}{t^{7-5}u^{4-2}} \\\\\\ \cfrac{-5}{12}\cdot \cfrac{v^2}{t^2u^2}\implies \cfrac{-5v^2}{12t^2 u^2}

3 0
3 years ago
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