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Fed [463]
3 years ago
13

What is the purpose of writing Shorthand Electron Configuration Using Noble Gases?

Chemistry
1 answer:
stepan [7]3 years ago
6 0

Noble gas electron configurations are easier to write because they are shorter then full electron configurations. They Noble gas shortcut electron configuration is a way of summarizing the information about the electrons of an atom. 


(this is what I used)

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The energy needed to remove an electron from an atom is called
Arlecino [84]

Ionization energy, also called ionization potential, in chemistry, the amount of energy required to remove an electron from an isolated atom or molecule

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Obtain a box of breakfast cereal and read the list of ingredients. What are four chemicals from the list? a. monoglycerides b. c
GREYUIT [131]

Answer:

B. cocamide DEA

C. folic acid

D. iron

G. lauryl glucoside

5 0
3 years ago
What type(s) of intermolecular forces are expected between ch3ch2ch2ch2ch2ch2oh molecules?
EleoNora [17]
Listed below are the inter-molecular bonding that exists in the compound <span>ch3ch2ch2ch2ch2ch2oh.

1. Hydrogen Bonding- The type of bonding that exist between O-H in the compound.
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3 0
3 years ago
How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-k
weeeeeb [17]
Ideal gas law: PV = nRT

P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature

State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)

Sub in:
(203kPa)(10L)=n(8.31)(298)

Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample
8 0
3 years ago
If a balloon containing 3000 L of gas at 39°C and 99 kPa rises to an altitude where the pressure is 45.5 kPa and the temperature
ludmilkaskok [199]

\tt =3000~L\times \dfrac{289}{312}\times \dfrac{99}{45.5}

<h3>Further explanation</h3>

Given

3000 L of gas at 39°C and 99 kPa to 45.5 kPa and 16°C,

Required

the new volume

Solution

Combined with Boyle's law and Gay Lussac's law  

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

T₁ = 39 + 273 = 312

T₂ = 16 + 273 = 289

Input the value :

V₂ = (P₁V₁.T₂)/(P₂.T₁)

V₂ = (99 x 3000 x 289)/(45.5 x 312)

or we can write it as:

V₂ = 3000 L x (289/312) x (99/45.5)

3 0
3 years ago
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