Answer:
A. 1:3
Explanation:
If we look at the ions shown in the image attached to the question, we will notice that we have aluminum (Al^3+), a trivalent ion combining with the iodide ion (I^-).
Aluminum can easily give out its three outermost electrons to three atoms of iodine. If aluminum gives out its three electrons, it achieves the stable octet structure. Iodine atoms have seven electrons in their outermost shell. They only need one more electrons to complete their octet. This one electron can be gotten by the combination of three iodine atoms with one atom of aluminum. One electron each is transferred from the aluminum atom to each iodine atom to form AlI3 with a ratio of 1:3.
In order for carbon to be stable and have 8 electrons, it must make 4 total covalent bonds.
In prefer for oxygen to be stable and have 8 electrons, it must make 2 covalent bonds.
So, we can deduce that CO2 looks like this:
O=C=O
This molecule has two double bonds.
Pssst...Can I get a brainliest?
Answer:
To interpret a 13C-NMR spectrum we will use some standards very simple. A 13C-NMR spectrum gives us the following information:
1. Indicates the number of non-equivalent carbons in the molecule.
2. Measuring the chemical shift we can intuit the environment
electronic and determine the next functional groups.
3. In this case we cannot count on integration since the different
carbons have different relaxation times.
The number of peaks in the spectrum indicates the number of types of carbon present in the analyzed substance.
The factors that influence the chemical shift of the signals in the 13C NMR are:
- electronegativity of carbon bound groups
-
carbon hybridization
Explanation:
The nuclear magnetic resonance of C13 is complementary to that of H1. This technique is used to determine the magnetic environment of carbon atoms.
Answer:
C) 712 KJ/mol
Explanation:
- ΔH°r = Σ Eb broken - Σ Eb formed
- 1/2Br2(g) + 3/2F2(g) → BrF3(g)
∴ ΔH°r = - 384 KJ/mol
∴ Br2 Eb = 193 KJ/mol
∴ F2 Eb = 154 KJ/mol
⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)
⇒ Σ Eb broken = (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol
∴ Eb formed: Br-F
⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r
⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )
⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol
Yes I think it’s look right to me
