Calculate the percent ionic, the percent covalent, and the bond length (in picometers) of a chemical bond between phosphorus and
1 answer:
Answer:
The correct option is;
4 percent ionic, 96 percent covalent, 222 pm
Explanation:
The parameters given are;
Phosphorus:
Atomic radius = 109 pm
Covalent radius = 106 pm
Ionic radius = 212 pm
Electronegativity of phosphorus = 2.19
Selenium:
Atomic radius = 122 pm
Covalent radius = 116 pm
Ionic radius = 198 pm
Electronegativity of selenium= 2.55
The percentage ionic character of the chemical bond between phosphorus and selenium is given by the relation;
Using Pauling's alternative electronegativity difference method, we have;
Where:
Δ E.N. = Change in electronegativity = 2.55 - 2.19 = 0.36
Therefore;
Hence the percentage ionic character = 4.3% ≈ 4%
the percentage covalent character = (100 - 4.3)% = 95.7% ≈ 96%
The bond length for the covalent bond is found adding the covalent radii of both atoms as follows;
The bond length for the covalent bond = 106 pm + 116 pm = 222 pm.
The correct option is therefore, 4 percent ionic, 96 percent covalent, 222 pm.
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Answer:
The Lewis structures are shown in the figure
Explanation:
The lewis structure will be drawn using following steps
i) we will calculate the total number of valence electrons in the molecule
ii) will assign one bond (two electrons in between two atoms)
iii) then distribute the rest of the valence electrons as lone pair or shared pair based on completion of octet.
The structure of each molecule is given in the figure.
Valence electrons:
V.E = 5 +(2)6-1=16
V.E =5 +(2)6+7=24
