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3 years ago

Which pair of angles is a linear pair?

Mathematics

1 answer:

Oksana_A [137]3 years ago

5 0

All of them because a linear pair is when two lines intersect

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Write 9− 16x⁴ as the product of two factors.

Marysya12 [62]

Answer:

The two factors will be $=(3+4x^2)\ and\ (3-4x^2)$

Step-by-step explanation:

We have given the equation $9-16x^4$

We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

As $9-16x^4$ can be written as $3^2-(4x^2)^2$ , as square of 3 is 9 and square of $4x^2$ is $16x^4$

So $9-16x^4=3^2-(4x^2)^=(3+4x^2)(3-4x^2)$

So the two factors will be $=(3+4x^2)\ and\ (3-4x^2)$

6 0

3 years ago

Which choice below is a common multiple of 8 and 10 (but not the least common multiple).

Ilya [14]

Answer:

160

Step-by-step explanation:

4 is too low, 90 cant be divided by 8 and 160 is the only answer even though it is highest number

8 0

3 years ago

Read 2 more answers

Solving quadratic equation<br>7r^2-14=-7

Gala2k [10]

I hope this helps you

7 0

3 years ago

Raina bought three books at a bookstore. Here are their prices (in dollars). 18.8, 4, 9.38 What is the total amount Raina paid a

artcher [175]

Answer:

$32.18

Step-by-step explanation:

It's really just addition. No explanation necessary.

4 0

3 years ago

But The aquarium charges $12 per ticket for adults and $5per ticket for children. A group of 90 children and adult chaperones vi

White raven [17]

Answer:

There were 76 childrens and 14 adults.

Step-by-step explanation:

Since the group has a total of 90 children and adults, then the sum of the number of adults with the number of children must be equal to 90 as shown below:

children + adults = 90

Since the total cost for their tickets was 548 then the number of children multiplied by the price of their ticket summed by the number of adults multiplied by the price of their ticket must be equal to that. We have:

5*children + 12*adults = 548

With these two equations we have a system of equations shown below:

children + adults = 90

5*children + 12*adults = 548

In order to solve this we will multiply the first equation by -5, and sum both equations we have:

-5*children - 5*adults = -450

5*children + 12*adults = 548

7*adults = 98

adults = 98/7 = 14

children + 14 = 90

children = 90 - 14 = 76

There were 76 childrens and 14 adults.

7 0

3 years ago