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Otrada [13]
3 years ago
8

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Chemistry
2 answers:
horsena [70]3 years ago
8 0

Answer:

hows this chemistry

Explanation:

iren [92.7K]3 years ago
5 0

Answer:

you're twelve and looking for a relationship online??? wth

Explanation:

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A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33
ANEK [815]

Explanation:

The given data is as follows.

     Vapour pressure of pure CCl_{4} = 33.85 Torr

         Temperature = 298 K

      Mole fraction of Br_{2} = 122.36 torr

Therefore, calculate the vapor pressure of Br_{2} as follows.      

     Vapour pressure of Br_{2} = mole fraction of Br_{2} x K of Br_{2}

                                    = 0.050 x 122.36 Torr

                                   = 6.118 Torr

So, vapor pressure of Br_{2} is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

     Vapour pressure of CCl_{4} = mole fraction of CCl_{4} x Pressure of CCl_{4}

                                     = (1 - 0.050) × 33.85 Torr

                                     = 32.1575 Torr

So, vapor pressure of CCl_{4} is 32.1575 Torr  .

Hence, the total pressure will be as follows.

                         = 6.118 Torr + 32.1575 Torr

                         = 38.2755 Torr

Therefore, composition of CCl_{4} = \frac{32.1575 Torr}{38.2755 Torr}

                         = 0.8405

Composition of CCl_{4} is 0.8405 .

And, composition of Br_{2} = \frac{6.118 Torr}{38.2755 Torr}

                                                  = 0.1598

Composition of Br_{2} is 0.1598 .

6 0
3 years ago
I need help with this question
Leviafan [203]

Answer:

i do not know the answer but pls give a heart and five starts so i can ask questions pls

Explanation:

3 0
3 years ago
An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar
Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

         372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    = 4526 g/s \times -26.5 kJ/g

                    = 1.19 \times 10^{5} kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is 1.19 \times 10^{5} kW.

5 0
3 years ago
The _______________________________________ is often referred to as the powerhouse of the cell
almond37 [142]

Answer:

Mitochondria

Explanation:

7 0
3 years ago
Read 2 more answers
A sample of chlorine gas is held at a pressure of 1023.6 kPa. When the pressure is decreased to 8114 kPa the
eduard

Answer:

T₁  = 39 K

Explanation:

Given data:

Initial pressure = 1023.6 kpa

Final pressure = 8114 kpa

Final temperature = 36°C (36+ 273= 309K)

Initial temperature = ?

Solution:

P₁/T₁ = P₂/T₂

T₁  = P₁×T₂ /P₂

T₁  = 1023.6 kpa × 309 K /8114 kpa

T₁  = 316292.4 K. Kpa /8114 kpa

T₁  = 39 K

Thus original pressure was 39 k.

3 0
3 years ago
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