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choli [55]
2 years ago
5

How Could Spectroscopy Be Used to Distinguish Between the Following

Chemistry
1 answer:
skelet666 [1.2K]2 years ago
5 0

Spectroscopy be used to distinguish between the following is the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

<h3>What is spectroscopy?</h3>

Spectroscopy is the study of emission or absorption of light. It is used to study the structure of atoms and molecules.

The three types of spectroscopy are:

  • atomic absorption spectroscopy (AAS)
  • atomic emission spectroscopy (AES)
  • atomic fluorescence spectroscopy (AFS)

Thus, the correct option is B, the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

Learn more about spectroscopy

brainly.com/question/5402430

#SPJ1

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A gas that effuses through a porous cylinder 1.87 times faster than chlorine gas. what is the molar mass and identity.
Rufina [12.5K]
From the Graham's law of effusion;
R1/R2 = √MM2/√MM1
Molar mass of chlorine gas is 71
Therefore;
1.87= √ 71 /√mm1
= 1.87² = 71/mm1 
mm1 = 71/1.87²
         = 71/3.4969
         = 20.3
Thus, the molar mass of the other gas is 20.3 , and i think the gas is neon
6 0
3 years ago
The solubility of lead(ii) chloride is 0.45 g/100 ml of solution. what is the ksp of pbcl2? 4.9 × 10-2 1.7 × 10-5 8.5 × 10-6 4.2
Artyom0805 [142]
Answer:
1.7 * 10^-5

Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
number of moles = 0.45 / 278.1 = 1.618 * 10^-3 moles

2- get the concentration of Pb2+:
molarity = number of moles of solute / volume of solution in liters
molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M

3- getting concentration of Cl-:
<span>PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq) 
</span>We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed

4- getting Ksp:
Ksp = [Pb2+][Cl-]²
Ksp = (0.0162)*(0.0324)²
Ksp = 1.7 * 10^-5

Hope this helps :)
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