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BlackZzzverrR [31]
3 years ago
6

Wolff-kishner reduction (hydrazine, koh, ethylene glycol, 130°c) of the compound shown gave compound

Chemistry
1 answer:
telo118 [61]3 years ago
8 0
The scheme is shown below, the steps involved are as follow,

Step one: Reduction:
               The carbonyl group of given compound on reduction using Wolf Kishner reagent converts the carbonyl group into -CH₂- group.

Step two: Epoxidation:
              The double bond present in starting compound when treated with m-CPBA (<span>meta-Chloroperoxybenzoic acid) gives corrsponding epoxide.

Step three: Reduction:
                The epoxide is reduced to alcohol on treatment with Lithium Aluminium Hydride (LiAlH</span>₄)<span> followed by hydrolysis.

Step four: Oxidation:
               The hydroxyl group (alcohol) is oxidized to carbonyl (ketonic group) using oxidizing agent Chromic acid (H</span>₂CrO₄).

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